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3 years ago

Find the shaded area

Mathematics

1 answer:

grin007 [14]3 years ago

5 0

Answer:

area of big rectangle=l×b=12×18=216cm²

area of smaller square=l²=8²=64cm²

area of shaded area =area of (bigger rectangle-smaller square)=216-64=152cm²

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Customers' sandwich choices one day at ray's lunch counter are shown.

oee [108]

If you read the question you can find that some requirements were missing. By Googling the Question the complete content could be found here:

https://www.chegg.com/homework-help/questions-and-answers/ved-restore-nu-sge-essments-testnavaspx-idassessment-1591215-idwebuser-30156018idsection-1-q44055003

The relative frequencies missing in the table are :

ham-wheat = 0.231, cheese-wheat = 0.0.462.

rye-turkey = 0.167, rye-ham = 0.417.

<u> Step-by-step explanation: </u>

From the given data we have to count the frequencies of wheat and rye chosen to find the missing values.

The frequency of wheat chosen = 13.

The frequency of rye chosen = 12.

Relative Frequency can be obtained by dividing the combined frequency by the total number of data values.

Wheat combinations:

1) The frequency of ham-wheat = 3.

Then the relative frequency of ham-wheat = $\frac{3}{13}$ .

The the relative frequency of ham-wheat = 0.230769 or 0.231.

2) The frequency of cheese-wheat = 6.

Then the relative frequency of cheese-wheat = $\frac{6}{13}$ .

The the relative frequency of cheese-wheat = 0.4615 or 0.0.462.

Rye combinations:

1) The frequency of rye-turkey = 2.

Then the relative frequency of rye-turkey = $\frac{2}{12}$ .

The the relative frequency of rye-turkey = 0.1666 or 0.167.

2) The frequency of rye-ham = 5.

Then the relative frequency of rye-ham = $\frac{5}{12}$ .

The the relative frequency of rye-ham = 0.41667 or 0.417.

8 0

3 years ago

Find each product or quotient. Use significant digits. 1,370 m ¸ 31.7 s

marusya05 [52]

<span>v = 1370/31.7 m/s
=43.21m/s
hope this helps</span>

6 0

3 years ago

Tain has a great literary tradition that spans centuries. One might assume, then, that Britons read more than citizens of other

tresset_1 [31]

Answer:

Null hypothesis: $p_{1} \leq p_{2}$

Alternative hypothesis: $p_{1} > p_{2}$

$z=3.02$

$p_v =P(Z>3.02)=0.00127$

The p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of Canadians is not significantly higher than the porportions of readers at Britons.

Step-by-step explanation:

1) Data given and notation

$X_{1}=0.86*1004$ represent the number of Canadians randomly sampled by Gallup that read at least one book in the past year

$X_{2}=0.81*1009$ represent the number of Britons randomly sampled that read at least one book in the past year

$n_{1}=1004$ sample of Gallup selected

$n_{2}=1009$ sample of Britons selected

$p_{1}=0.86$ represent the proportion of Canadians randomly sampled by Gallup that read at least one book in the past year

$p_{2}=0.81$ represent the proportion of Britons randomly sampled that read at least one book in the past year

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportion for men with red/green color blindness is a higher than the rate for women , the system of hypothesis would be:

Null hypothesis: $p_{1} \leq p_{2}$

Alternative hypothesis: $p_{1} > p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{0.81+0.86}{2}=0.835$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.86-0.81}{\sqrt{0.835(1-0.835)(\frac{1}{1004}+\frac{1}{1009})}}=3.02$

4) Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =P(Z>3.02)=0.00127$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of Canadians is not significantly higher than the porportions of readers at Britons.

5 0

4 years ago

Which number line model represents the expression 3.5+(-5)

Anarel [89]

Answer:

Step-by-step explanation:

7 0

3 years ago

HELP ME ASAP !!!!! ITS DUE TODAY

denis23 [38]

Answer a:

Figure 4 = 5 blocks up, 5 blocks right

Figure 5 = 6 blocks up, 5 blocks right

Answer b: Grows 2 blocks each time, 1 blocks at the top and 1 blocks on the right.

Answer c: Since you add 2 blocks each time, you do the opposite so you subtract 2 blocks. The answer will be 1 block.

Step-by-step explanation:

7 0

3 years ago