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Basile [38]
3 years ago
7

How can I set up a wildflower classification key?

Biology
1 answer:
s344n2d4d5 [400]3 years ago
3 0

Answer:

There are 3 methods to set up a wildflower classification means discovering a new flower. Those methods are discussed below in the explanation section.

Explanation:

Method one (Identification tools using):

  1. Search the about of the flower in the flower dictionary or flower database.
  2. Use any app which can identify flower such as Flowerchecker, Naturegate, etc.
  3. Take photos of the plant and post it on Flicker to get more information.
  4. Try google photos for searching about the plant by its picture.

Method two( Measuring the physical character of the plant):

  1. Measure the overall height of the plant.
  2. Measuring the width of the plant.
  3. Look at the flower to check how the flower is arranged on the stem.
  4. Count the petal number of the flower.
  5. Identify the color of the petals.
  6. Check the shape and texture of the stem.
  7. Check the shape, size, and arrangement of the leaves in the plant.
  8. Use this collected information to identify the flower in a plant database or encyclopedia.

Method three (Identifying the Flower’s Location and Blooming Time):

  1. Use the climate and terrain to determine the type of the flower.
  2. Observation of the factors in the geographic location to identify the flower.
  3. Find out the time of year when the flower bloomed.
  4. Identify the flower in an online database or encyclopedia using the collected information.

By doing this, you can set up a wildflower classification key and can find out the kingdom, family etc of the flower.

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Explanation:

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                 2pq=frequency of heterozygous genotype

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here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as:     q^2=0.0004

  • If q^2=0.0004 q will be 0.02;frequency of recessive allele will be 0.02
  • Using the formula p+q=1

                                       p+0.02=1\\p=1-0.02=0.98

  • hence,frequency of dominant allele will be 0.98
  • Frequency of dominant genotype will be p^2=(0.98)^2=0.9604
  • Frequency of heterozygous genotype will be 2pq=2*0.98*0.02=0.0392

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