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azamat
3 years ago
9

Estimate each quotient by first rounding each number to the nearest ten.

Mathematics
1 answer:
ololo11 [35]3 years ago
8 0
This is not super clear you need to give more detail.
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100% of what number is 61
Dominik [7]

" 100% " means "the whole thing",
and "is" can be replaced by "is equal to".

You have said "The whole thing of a number is equal to 61."
or
                       "61 is equal to the whole thing of a number."

The only number that 61 can be equal to is 61.

3 0
3 years ago
Read 2 more answers
A rectangle has a perimeter of 30 inches.
erastova [34]
The new perimeter would be 60. because the width and the height are doubled.
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3 years ago
Which equation below has no solution?
soldier1979 [14.2K]

Answer:

B

Step-by-step explanation:

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Consider a company that selects employees for random drug tests. The company uses a computer to select randomly employee numbers
andrew11 [14]
This problem sounds so ridiculous lol

All joking aside, first let's look at the multiples of 1000.

1000, 2000, 3000, 4000, 5000, 6000

That makes 6.  Complete the following equation, and you have your answer.

6 / 6296 = ?

0.000953 if you round.

Hope it helps. XD
8 0
3 years ago
Discrete Math
andrezito [222]

Answer:

Part c: Contained within the explanation

Part b: gcd(1200,560)=80

Part a: q=-6         r=1

Step-by-step explanation:

I will start with c and work my way up:

Part c:

Proof:

We want to shoe that bL=a+c for some integer L given:

bM=a for some integer M and bK=c for some integer K.

If a=bM and c=bK,

then a+c=bM+bK.

a+c=bM+bK

a+c=b(M+K) by factoring using distributive property

Now we have what we wanted to prove since integers are closed under addition.  M+K is an integer since M and K are integers.

So L=M+K in bL=a+c.

We have shown b|(a+c) given b|a and b|c.

//

Part b:

We are going to use Euclidean's Algorithm.

Start with bigger number and see how much smaller number goes into it:

1200=2(560)+80

560=80(7)

This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.

Part a:

Find q and r such that:

-65=q(11)+r

We want to find q and r such that they satisfy the division algorithm.

r is suppose to be a positive integer less than 11.

So q=-6 gives:

-65=(-6)(11)+r

-65=-66+r

So r=1 since r=-65+66.

So q=-6 while r=1.

3 0
3 years ago
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