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const2013 [10]
3 years ago
5

Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet:

1.25 cups of dry food. Based on these averages, how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks? *
Mathematics
1 answer:
Phoenix [80]3 years ago
3 0

6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find  how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

Trenton's pet: 4/5 cup of dry food•

With 4/5 per day , for 14 days :

⇒ 14(\frac{4}{5} )

⇒ 14(0.8 )

⇒ 11.2

Maria's pet: 1.25 cups of dry food.

With 1.25 per day , for 14 days :

⇒ 14(1.25 )

⇒ 17.5

Subtracting Maria's - Trenton's :

⇒ 17.5-11.2=6.3

That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

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Answer:

Louis has faster pitch when compared to each of their teams.

Step-by-step explanation:

We have two pitchers which we need to compare to each of their teams.

To calculate this, we will approximate the distributions to a normal distribution, and calculate the z-score, to know what proportion of players of their team fall below their score.

For Jerry, he has a speed of 86 and his team has a mean speed of 93 and standard deviation of 3.

We can calculate the z-score for Jerry speed as:

z=\dfrac{X-\mu}{\sigma}=\dfrac{86-93}{3}=\dfrac{-7}{3}= -2.333

The proportion of players that are below Jerry speed is approximated by the standard normal distribution:

p=\Phi(z

For Louis, his speed is 84 and his team has a mean speed of 89 and standard deviation of 3.5.

We can calculate the z-score for Jerry speed as:

z=\dfrac{X-\mu}{\sigma}=\dfrac{84-89}{3.5}=\dfrac{-5}{3.5}= -1.429

The proportion of players that are below Louis speed is approximated by the standard normal distribution:

p=\Phi(z

As the proportion of players of Louis team that are below Louis speed is much bigger than the proportion of players of Jerry's team that are below Jerry speed, we can say that Louis has faster pitch when compared to each of their teams.

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m is the slope of the line, which can be calculated using the equation:
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3 years ago
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Anton will be constructing a segment bisector with a compass and straightedge, while Maxim will be constructing an angle bisecto
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The <u>similarities</u> between their construction are:

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Visit: brainly.com/question/17247176

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