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3 years ago

If the formula pictured below is used to find the mean of the following sample, what is the value of N?

Mathematics

2 answers:

Pie3 years ago

8 0

Answer:

Choice D). 8

Step-by-step explanation:

The value on n is simply the number of values or the size of the sample data. In our case, we have a total of 8 data values. The value of n will thus be 8

creativ13 [48]3 years ago

8 0

Answer:

Choice D is correct answer.

Step-by-step explanation:

We have given a list of values.

2,63,88,10,72,99,38,19

We have to find mean and value of n.

n is the total number of values.

Hence, n = 8

Formula to find mean is :

Mean = sum of values / number of values

Sum of values = 2+63+88+10+72+99+38+19 = 391

Number of values = 8

Mean = 391/8

Mean = 48.875

Mean of the following sample is 48.875

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The number of letters in Stephanie's full name is sixteen less than twice the number of letters in Amy's full name. If the numbe

Anestetic [448]

Answer:

19 letters

Step-by-step explanation:

Suppose Number of Amy's full name letters = X

Number of Stephanie's full name letters = Y

Now, according to given condition that ''number of letters in Stephanie's full name is sixteen less than twice the number of letters in Amy's full name'',

Equation 1 becomes

Y = 2X-16

Now, according to second condition, product of their names' letter is 418. So,

Equation 2 becomes

XY = 418

Deducing value of X from equation 1,

X = (Y+16)/2

Putting this value in equation 2 we get,

{(Y+16)/2}*Y = 418,

By simplifying this equation we get a quadritic equation

(Y^2)+16Y-836=0

By breaking middle term (You can use quadratic formula here as well)

(Y^2)+38Y-22Y-836=0

Y(Y+38)-22(Y+38)=0

(Y-22)(Y+38)=0

At this stage we have two values for Y,

Y=22, or Y=-38

Now considering only positive value since the number of letters in a name can not be in negative number,

Y=22,

So X=(Y+16)/2

X=19

7 0

3 years ago

I need help on this problem. I got half of it right but I don’t know how I got the last answer wrong... Can anyone please help m

morpeh [17]

I got the same answer as you. Try to ask your teacher about it since it’s a math problem online or something.

8 0

3 years ago

What are the 5 infinitives?

Ymorist [56]

The five types of infinitives are full infinitives, bare infinitives, split infinitives, continuous infinitives , and perfect continuous infinitive.

Explanation:

Types of infinitives:

Five types of infinitives are as follow:

Full infinitives : Add 'to' Infront of the verb to complete the the situation.

Bare infinitives: here " to" get omitted from the sentence.

Split infinitives : Here adjectives slides between infinitives marker.

To hear : full infinitives changes to split infinitives : to slowly hear.

Continuous infinitives: Action going for certain period of required time.

Example : to be missing

Perfect continuous infinitives: prior to a time :

Example : to have seen

Therefore, there are are five types of infinitives .

Learn more about infinitives here

brainly.com/question/1219442

#SPJ4

5 0

1 year ago

(WILL GIVE BRAINLIEST) In right ∆ABC with m∠B=30°, AC = 4. Find HB

goblinko [34]

Answer:

HB would be 90 degrees

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

4 0

3 years ago