Answer and work down below. Let me know if you have any questions
The 4C matrix is obtained when all elements of matrix C are multiplied by 4. It <span>has all the same elements as C, only multiplied by 4.
Let's analyze all matrices
A. Not all elements of A can be divided by 4 (3 can not be divided by 4, the solution is not a whole number).
B. All elements of matrix B can be divided by 4, which means that B is a $C matrix (there is a matrix C which multiplied by 4 gives the matrix B).
C. Not all elements of C can be divided by 4.
D. Not all elements of D can be divided by 4.
Solution: B
</span>
Answer:
x = 42
Step-by-step explanation:
166 + 93 + 127 + 112=498
5-2=3
180 x 3=540
540-498=42
|6x – 1| + 4 = 1
isolate the absolute value
subtract 4 from each side
|6x – 1| + 4-4 = 1-4
|6x – 1| = -3
There are no solutions since absolute value means always positive and the other side is negative
Answer:
it is basically 10*10=100
Step-by-step explanation:
