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Julli [10]
3 years ago
11

Evaluate 8•0.25-1+14

Mathematics
2 answers:
coldgirl [10]3 years ago
4 0

Answer:

Hey Mate

Answer is 15

Hope it helps

Andreyy893 years ago
4 0
15 is the correct answer :)
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Mr. Aleman is the treasurer for his local scouting troop. He makes a budget for the troop.He suggests that they spend 1/2 of the
kari74 [83]

Answer:

Answer: XII CCCXLV

Step-by-step explanation:

To convert 12,345 to Roman Numerals you have to take them apart into place values (ones, tens, hundreds).

Ten Thousands=10,000=X

Thousands=2,000=MM

Hundreds=300=CCC

Tens=40=XL

Ones=5=V

Step-by-step explanation:

7 0
3 years ago
Find the equation of the line that Contains the point (4,-2) and is perpendicular to the line y = -2x+5
MaRussiya [10]
Y=1/2x-4

Perpendicular means it is opposite and the reciprocal. 1/2(4) = 2-4 equals -2.
(4,-2)
4 0
3 years ago
Hey sugar cookie recipe calls for three 1/2 cup of sugar to make six dozen cookies based on the recipe how many cups of sugar mu
wariber [46]
It is 3.33 repeating cups of sugar
4 0
4 years ago
Read 2 more answers
Help pure people pls
Sedaia [141]

Answer:

Option (B). Perimeter of the quadrilateral ABCD= 14.6 units

Step-by-step explanation:

From the figure attached,

Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).

Length of AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

                      = \sqrt{(3-1)^2+(5-3)^2}

                      = \sqrt{8}

                      = 2.83 units

Length of AD = \sqrt{(3-5)^2+(5-3)^2}

                      = \sqrt{8}

                      = 2.83 units

Length of BC = \sqrt{(1-3)^2+(3+1)^2}

                      = \sqrt{20}

                      = 4.47 units

Length of DC = \sqrt{(5-3)^2+(3+1)^2}

                       = \sqrt{20}

                       = 4.47 units

Perimeter of the quadrilateral = AB + AD + DC + BC

                                                 = 2.83 + 2.83 + 4.47 + 4.47

                                                = 14.6 units  

Option (B) is the answer.

7 0
3 years ago
Factor and find the zeros of the relation.
Nady [450]

Answer:

Step-by-step explanation:

c.

y= 30x² +44x +16

factor

y= 2 (15x² +22x +8)

find zeros

15x²+22x+8=0

ax²+bx+c=0

x= (-b±√(b²-4ac))/2a

x= -22±√484-480/30 = -22±2/30 = -11±1/15

there are 2 zeros x= -10/15 ; x= -12/15

d.

y= 10x² +60x +80

factor

y= 10(x²+6x+8) = 10( x+2)(x+4)

finding zeros

x+2 =0 so x= -2

x+4 =0 so x= -4

there are 2 zeros x= -2; x= -4

4 0
3 years ago
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