Answer:
1,000,000
Step-by-step explanation:
Answer:
0, -1
Step-by-step explanation:
zeros occur when 2x^6+2x^5=0
the first way for this to happen would be to set x to 0. both terms would become zero.
the second way is x = -1
first term becomes 2
second becomes -2
these add to zero
Answer:
4 right angles
Step-by-step explanation:
a straight light intersects another straight line= creating 4 right angles
Step-by-step explanation:
z
3
=8(cos216
∘
+isin216
∘
)
z^3=2^3(\cos(6^3)^\circ+i\sin(6^3)^\circ)z
3
=2
3
(cos(6
3
)
∘
+isin(6
3
)
∘
)
\implies z=8^{1/3}\left(\cos\left(\dfrac{216+360k}3\right)^\circ+i\sin\left(\dfrac{216+360k}3\right)^\circ\right)⟹z=8
1/3
(cos(
3
216+360k
)
∘
+isin(
3
216+360k
)
∘
)
where k=0,1,2k=0,1,2 . So the third roots are
\begin{gathered}z=\begin{cases}2(\cos72^\circ+i\sin72^\circ)\\2(\cos192^\circ+i\sin192^\circ)\\2(\cos312^\circ+i\sin312^\circ)\end{cases}\end{gathered}
z=
⎩
⎪
⎪
⎨
⎪
⎪
⎧
2(cos72
∘
+isin72
∘
)
2(cos192
∘
+isin192
∘
)
2(cos312
∘
+isin312
∘
)
Answer:
123
Step-by-step explanation:
if the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadth
