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2 years ago

14

Margie has 28 feet of trim to use as edging on a rectangle blanket she wants to make what is the length and width of the two bla

nkets

1 answer:

Kryger [21]2 years ago

6 0

Okay first you have to divide.... so what goes into 28
it would be 4 divided into 28 and that gives up 7 so the answer is 7 feet

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Write in slope-intercept form an equation of the line that passes through the given points.

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3 years ago

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I need help please.

Greeley [361]

Answer is C).

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3 years ago

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2 years ago

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time

cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

$1\leq t\geq \sqrt{2}$

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

$h =20-5t^{2}$ -----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height $h = 15m$

Put height value in equation 1

$15 =20-5t^{2}$

$5t^{2} =20-15$

$5t^{2} =5$

$t^{2} =1$

$t =\pm1$

We know that the time is always positive, therefore $t=1$

when the stuntman is 10m above the ground.

height $h = 10m$

Put height value in equation 1

$10 =20-5t^{2}$

$5t^{2} =20-10$

$5t^{2} =10$

$t^{2} =\frac{10}{5}$

$t^{2} =2$

$t=\pm\sqrt{2}$

$t=\sqrt{2}$

Therefore ,time interval of camera film him is $1\leq t\geq \sqrt{2}$

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3 years ago

The frequency table shows the students' scores on a recent math test.what percentage of the students scored at least 81 on the t

Irina18 [472]

Answer:

54%

Step-by-step explanation:

total students are 50

20+7 scored at least 81 = 27

27/50=54%

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2 years ago

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