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worty [1.4K]
3 years ago
5

PLZ ANSWER QUICKLY :)

Mathematics
1 answer:
svetlana [45]3 years ago
6 0

The answer is p v q and some other one, I haven't done logic in 2 years already, so I don't know the other one. BUT, if p is true, then p v q HAS to be true because if one of the statements, p or q, is true, then p v q is true. For or statements to be true, at least one of the statements included has to be true.

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PLEASE HELP ME ITS ALGEBRA THANK YOUUUU
vampirchik [111]

Answer: 2,208$

Step-by-step explanation:

To solve this problem, simply determine how much each attendee costs by doing 960$/30attendees = 32$/attendee.  Then, simply multiply this number by 69 to get: 2,208$

Hope it helps :) and let me know if you want me to elaborate further.

3 0
2 years ago
How many groups of 3/4 are in each of the following quantities? 6 1/2<br> answer as a fraction
Allushta [10]
8 2/3

because 6 1/2 divided by 3/4 is 8 2/3
7 0
3 years ago
Luis es repartidor de leche el tiene 534 bolsas y las reparte entre cierto numero de tienda de modo que a cada le corresponde 28
OlgaM077 [116]
The first thing we must keep in mind is that there are 2 bags left over.
 Therefore, Luis distributed:
 534-2 = 532
 The number of bags will be:
 N = (total amount distributed) / (amount distributed per store)
 Substituting we have:
 N = (532) / (28)
 N = 19
 Answer:
 
Luis distributed milk for 19 stores.
8 0
3 years ago
Find the 11th term of the geometric sequence 6, -18, 54
Nataly [62]
I don’t feel like doing it but I we’ll tell you how to do it you multiply it by 3 so 6 x 3 equals 18 just in negative do 18 x 3 equal 54 so every other on is a negative it’s Simone
4 0
3 years ago
If two polygons are SIMILAR, then the corresponding sides must be and the corresponding angles must be .
AveGali [126]

Answer:

Their sides must be in the same ratio and their angles must be equal.

Step-by-step explanation:

If two polygons are similar their sides must be in the same ratio and their angles must be equal.

e. g. -

If ABCDEF  and GHIJKL be the two polygons,

then,

\frac{AB}{GH} = \frac{BC}{HI} = \frac{CD}{IJ} = \frac {DE}{JK} = \frac {EF}{KL} = \frac{FA}{LG}

and,

∠ABC = ∠GHI ; ∠BCD =∠HIJ ; ∠CDE = ∠IJK ; ∠DEF =∠JKL ; ∠EFA =∠KLG;

∠FAB = ∠LGH .

5 0
3 years ago
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