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3 years ago

A rectangular room is 22 meters longer than it is wide, and its perimeter is 1616 meters. find the dimension of the room.

1 answer:

3 0

W= width; L= length =w+22m; p= perimeter= 2(L+w)
1616 meters= 2 (L+w) substitute for L
1616m+ 2(w+22m+w) divide each side by 2

808m= 2w+22m subtract 22m from each side
786m=2w divide each side by 2
393m=w Anwer: The width is 393 meters
L=w+22m=393m+22m=415m Answer: The length is 415 meters

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Im almost done with it

baherus [9]

Answer:

Area of rectangle = $\mathbf{x^2-4x}$

Perimeter of rectangle = $\mathbf{4x-8}$

Step-by-step explanation:

We are given:

Length of rectangle = x

Width of rectangle = x-4

We are not given if we want to find area of rectangle or perimeter of rectangle.

So, I will be finding both

Area of rectangle

The formula used is: $Area\: of\: rectangle=Length \times Width$

Putting values and finding area

$Area\: of\: rectangle=Length \times Width\\Area\: of\: rectangle=x \times (x-4)\\Area\: of\: rectangle=x^2-4x$

So, we get area of rectangle = $\mathbf{x^2-4x}$

Perimeter of rectangle

The formula used is: $Perimeter \: of\: rectangle=2(Length+ Width)$

Putting values and finding perimeter

$Perimeter \: of\: rectangle=2(Length+ Width)\\Perimeter \: of\: rectangle=2(x+ x-4)\\Perimeter \: of\: rectangle=2(2x-4)\\Perimeter \: of\: rectangle=4x-8$

So, we get perimeter of rectangle = $\mathbf{4x-8}$

I hope, it can help in solving the question.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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