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jok3333 [9.3K]
4 years ago
14

I need to know how to solve this equation?

Mathematics
1 answer:
cestrela7 [59]4 years ago
8 0
Your picture shows the first step: use the distributive property to eliminate parentheses.
  5*7 -5*x = 2*x -3
Now, you have an equation with a constant and an x-term on each side. I like to pick the x-term with the smallest (most-negative) coefficient and add its opposite to the equation.

Adding 5x, we have
  35 = 7x -3
Adding 3 will get the x-term on one side and the constant on the other
  38 = 7x
Now, we divide by the coefficient of x
  38/7 = x = 5 3/7

This is the correct answer, even though it is not an integer.

_____
Check
  5(7 -(5 3/7)) = 2(5 3/7) -3 . . . . substitute for x in the original equation
  5(1 4/7) = 10 6/7 -3 . . . . . . . . . evaluate the parentheses on the left, do the multiplication on the right
  5 20/7 = 7 6/7 . . . . . . . . . . . . do the multiplicaton on the left, the subtraction on the right
  5 +2 6/7 = 7 6/7 . . . . . . . . . . . rewrite 20/7, realize 5+2=7. true
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8 0
4 years ago
Read 2 more answers
4. Find the value of x.
oksano4ka [1.4K]

Answer:

x = 50°

Step-by-step explanation:

The sum of the measures of the angles of a quadrilateral is 360°

360 - 40 - 80 - 110 = 130

130 is the measure of the quad that is adjacent to the angle of x° and is supplementary to that angle also.

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3 years ago
A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modele
aev [14]

THIS IS THE COMPLETE QUESTION

basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball reaches the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?

Yes, exactly 0.6 seconds after the shot is launched.

Yes, between 0.64 seconds and 0.65 seconds after the shot is launched

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

No, the shot is not blocked.

Answer:

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Given that the

equation for shot block height h = 9 + 25t – 16t2.

equation for ball height h = 6 + 30t – 16t2.

From the question ,it can be deducted that the shot is made before two tenths of a second or 0.2seconds

CHECK THE ATTACHMENT TO COMPLETE THE DETAILED SOLUTION

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vfiekz [6]
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