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wolverine [178]
3 years ago
13

A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modele

d by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker's outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball was on a path to reach the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?

Mathematics
1 answer:
aev [14]3 years ago
5 0

THIS IS THE COMPLETE QUESTION

basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball reaches the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?

Yes, exactly 0.6 seconds after the shot is launched.

Yes, between 0.64 seconds and 0.65 seconds after the shot is launched

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

No, the shot is not blocked.

Answer:

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Given that the

equation for shot block height h = 9 + 25t – 16t2.

equation for ball height h = 6 + 30t – 16t2.

From the question ,it can be deducted that the shot is made before two tenths of a second or 0.2seconds

CHECK THE ATTACHMENT TO COMPLETE THE DETAILED SOLUTION

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liubo4ka [24]

Answer:

At a speed of 57 mph for 8 hr a driver will travel 456 mi

Step-by-step explanation:

Here we have a summary of the letters for each variable:

Speed ---> r          (in units of mph)

Time ---> t            (in units of hr)

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These three variables are related by the next formula:

d = rt

In the data they give to you: 57 mph and 8 hr, they are telling you the r and the t, respectively:

r = 57 mph

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The only thing you have to do is replace the values:

d = rt    ---->     d = 57 mph x 8 hr

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