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3 years ago

There are 4 apple pies, Meredith uses 38 apples, what is the unit rate?

Mathematics

1 answer:

Vikentia [17]3 years ago

8 0

The unit rate is 9.5 or 9 1/2 apples per pie.

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Complete the square to solve the equation below.

IceJOKER [234]

I believe it’s D. X=2

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3 years ago

Harriet earns the same amount of money each day. Her gross pay at the end of 7 work days is 35h + 56 dollars. Which expression r

Aleks [24]

Answer:

The expression that represents her gross pay each day will be: $(5h+8)$ dollars.

Step-by-step explanation:

Suppose, Harriet's gross pay each day $= x$

So, her total gross pay for 7 work days $=7*x= 7x$

Given that, her gross pay at the end of 7 work days is $(35h + 56)$ dollars.

So, the equation will be.......

$7x= 35h+56 \\ \\ x=\frac{35h+56}{7}\\ \\ x=\frac{35h}{7}+\frac{56}{7}\\ \\ x=5h+8$

Thus, the expression that represents her gross pay each day will be: $(5h+8)$ dollars.

8 0

3 years ago

The quadrilateral ABCD has area of 58 in2 and diagonal AC = 14.5 in. Find the length of diagonal BD if AC ⊥ BD.

azamat

Answer:

(look in the the Step by step)

Step-by-step explanation:

When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.

.. A = (1/2)*d₁*d₂

Substituting the given information, this becomes

.. 58 in² = (1/2)*(14.5 in)*d₂

.. 2*58/14.5 in = d₂ = 8 in

The length of diagonal BD is 8 in.

4 0

2 years ago

Which of the following is an irrational number? A. π B. -16/3 C. 2.6 D. 18

victus00 [196]

Which of the following is an irrational number?

A. π

6 0

3 years ago

Read 2 more answers

How to solve this? \int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x

ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

$\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes} \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}$

5 0

3 years ago