What's the least common multiple (LCM) of 2, 6, and 8? A. 48 B. 24 C. 2 D. 12

yan [13]

Percent means per 100.
Per means divided by.
So you can change a number by multiplying it by 1. Anything over itself is 1 (except zero but that doesn't matter right now)

So multiply .6 by 100/100
So you get 60/100
or 60 per 100
or 60%.

So basically, just multiply by 100 and add the % sign!

4 0

3 years ago

Read 2 more answers

7 kids on the basketball team return sick from a weekend playing games at Lakenheath High school with a virus. The aggressive vi

Lilit [14]

Answer:

It would take 6 days for 500 students to be affected.

Step-by-step explanation:

Given that:

1. Seven kids returned with the virus.

2. The aggressive virus spreads at 130% each day.

We want to find how many days until 500 students are infected by the virus.

First day:

7 students have the virus, 130% of 7 student will contract the virus again.

130% of 7 = (130/100) × 7

= 1.3 × 7 = 9.1 ≈ 9

9 new students are affected

New total affected = 7 + 9 = 16 students.

Day 2:

Affected = 1.3 × 16 = 20.8 ≈ 20

New total affected = 20 + 16 = 36

Day3

Affected = 1.3 × 36 = 46.8 ≈ 46

New total affected = 36 + 46 = 82

Day4

Affected = 1.3 × 82 = 106.6 ≈ 106

New total affected = 106 + 82 = 188

Day5

Affected = 1.3 × 188 = 244.4 ≈ 244

New total affected = 244 + 188 = 432

Day6

Affected = 1.3 × 432 = 561.6 ≈ 561

New total affected = 561 + 432 = 993

Therefore, it would take 6 days for 500 students to be affected.

8 0

3 years ago

The table shows the results of a survey in which 10th-grade students were asked how many siblings (brothers and/or sisters) they

lesantik [10]

Answer:

70%

Step-by-step explanation:

Given

Number of Siblings: || 0 || 1 || 2 || 3

Number of Students: || 4 || 18 || 10 || 8

Required

Determine the probability of a student having at least one but not more than 2 siblings

First, we have to determine the total number of 10th grade students

$Total = 4 + 18 + 10 + 8$

$Total = 40$

The probability of a student having at least one but not more than 2 siblings = P(1) + P(2)

Solving for P(1)

P(1) = number of students with 1 sibling / total number of students

From the given parameters, we have that:

Number of students with 1 sibling = 18

So:

$P(1) = \frac{18}{40}$

Solving for P(2)

P(2) = number of students with 2 siblings / total number of students

From the given parameters, we have that:

Number of students with 2 siblings = 10

So:

$P(2) = \frac{10}{40}$

$P(1) + P(2) = \frac{18}{40} + \frac{10}{40}$

Take LCM

$P(1) + P(2) = \frac{18 + 10}{40}$

$P(1) + P(2) = \frac{28}{40}$

Divide numerator and denominator by 4

$P(1) + P(2) = \frac{7}{10}$

$P(1) + P(2) = 0.7$

Convert to percentage

$P(1) + P(2) = 70\%$

Hence, the required probability is 70%

6 0

3 years ago

HELP ASAP I NEED THIS DONE TODAY ⚠️⚠️⚠️

liraira [26]

Answer:

The lowest whole number must be 2 to make the comparison true...hope it helps:)

6 0

2 years ago

Perimeter is 26 feet and length is 6 feet what is the width

Charra [1.4K]

Hey!!

here is your answer >>>

If lenght and width are given, it must be a rectangle ,

the formula for the perimeter of rectnagle is

2 ( Lenght + breadth )

Lenght is 6ft

Width = ?

perimeter = 26

2 ( 6 + Width ) = 26

6 + Width = 13

Width = 7ft

Hope my answer helps!

3 0

3 years ago