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BabaBlast [244]
3 years ago
15

I NEED HELP PLEASE, THANKS! :)

Mathematics
1 answer:
agasfer [191]3 years ago
5 0

Answer:

The answer is 4th Choice

Step-by-step explanation:

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Pls help me I’m stuck
Korvikt [17]
90 + 49 = 139

180 - 139 = 41

x = 41
3 0
4 years ago
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Use a net to find the lateral area and the total surface area of the cereal box.
ziro4ka [17]
To find the lateral area you will find the area of all 4 faces that are perpendicular to the base.

You will multiply the side by the length (front/back) and the side by the width (sides).

12 x 8 = 96
12 x 2 = 24
120 square inches x 2 = 240 square inches

The lateral area is 240 square inches.

The area of the base is 8 x 2 = 16 square inches.

16 x 2 = 32 square inches

240 square inches + 32 square inches = 272 square inches is the surface area.
7 0
3 years ago
The width of a rectangle is the length minus 4 units. The area of the rectangle is 12 units. What is the width in units of the r
Genrish500 [490]

Answer:

width = 2 units

Step-by-step explanation:

If the length of a rectangle is (x) units, then that means that the width of a rectangle is x - 4 units.

the area of a rectangle is length * width

so just substitute the values that we have now.

x (length) * (x-4) width = 12 (area of rectangle)

so that gives us

x^2 - 4x =12

subtract 12 from both sides

x^2 - 4x - 12 =0

now factor this equation

x^2 + 2x - 6x -12 = 0

x(x+2) - 6(x+2) = 0

(x-6)(x+2) = 0

x = 6, or x = -2 REMEMBER THAT VALUE OF x = LENGTH, IT CANNOT BE NEGATIVE AS YOU CANT HAVE NEGATIVE VALUE OF A SIDE

length = 6, and width = 6 -4 = 2

8 0
3 years ago
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Plz help first right gets brainly
Anestetic [448]
A. Is not linear because is has no y
How this helped ya out! :D
6 0
3 years ago
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Use the functions to answer the question.
Ksivusya [100]
Composition function rule (f○g)(x) = f(g(x))
<em><u /></em><u>Given the separate functions</u>: f(x)=2x+1 and g(x)=x^2

(f\circ g)(-5)\rightarrow\text{ Composition Function Rule}\rightarrow f(g(-5))=2((5)^2)+1
\rightarrow2(25)+1=50+1=51
4 0
3 years ago
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