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3 years ago

Please help someone I have 5 min until I have to turn this in!!

Mathematics

2 answers:

MakcuM [25]3 years ago

6 0

Answer:

2a(squared) + 3a + 8

Step-by-step explanation:

MatroZZZ [7]3 years ago

4 0

Answer: 2a^2+11a+10

Step-by-step explanation:

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A park in a subdivision is triangular shaped. Two adjacent sides of the park are 487 feet a d 465 feet. The angle between the si

Vsevolod [243]

The answer is "b:16,508 square yards"

7 0

4 years ago

Read 2 more answers

Find exact values for sin θ and tan θ if cos θ = -4/9 and tan θ > 0.

julsineya [31]

Answer:

Part 1) $sin(\theta)=-\frac{\sqrt{65}}{9}$

Part 2) $tan(\theta)=\frac{\sqrt{65}}{4}$

Step-by-step explanation:

we have that

The cosine of angle theta is negative and the tangent of angle theta is positive

That means that the sine of angle theta is negative

step 1

Find $sin(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$cos(\theta)=-\frac{4}{9}$

substitute

$sin^{2}(\theta) +(-\frac{4}{9})^{2}=1$

$sin^{2}(\theta) +\frac{16}{81}=1$

$sin^{2}(\theta)=1-\frac{16}{81}$

$sin^{2}(\theta)=\frac{65}{81}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{65}}{9}$

Remember that

In this problem the sine of angle theta is negative

$sin(\theta)=-\frac{\sqrt{65}}{9}$

step 2

Find $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{65}}{9}$

$cos(\theta)=-\frac{4}{9}$

substitute the given values

$tan(\theta)=-\frac{\sqrt{65}}{9}:-\frac{4}{9}=\frac{\sqrt{65}}{4}$

3 0

4 years ago

Beaker A contains 1 liter which is 15 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

Tanzania [10]

Answer:

Add 1.25 litres of oil.

Step-by-step explanation:

Contents in beaker A implies;

15% of oil in 1 litre = 0.15 litres of oil

So that, there are 0.15 litres of oil and 0.85 litres of vinegar in beaker A.

Contents in beaker B implies:

55% of oil in 2 litres = 1.1 litres of oil

So that, thee are 1.1 litres of oil and 0.9 litres of vinegar in beaker B.

Half of contents of B poured into A implies that beaker A now contains:

0.15 litres + 0.55 litres = 0.7 litres of oil

0.85 litres + 0.45 litres = 1.3 litres of vinegar

The percentage of oil in A now = $\frac{0.7}{2}$ x 100%

= 35%

To increase the percentage of oil to 60%, then:

0.7 litres + 1.25 litres = 1.95 litres of oil

But the new total litres of the content in beaker A = 3.25 litres

So that;

$\frac{1.95}{3.25}$ x 100% = 60%

Therefore, to produce a mixture which is 60% oil, add 1.25 litres of oil.

7 0

3 years ago

Solve the system by substitution <br><br> -8x+y=-9<br> y=7

aleksandr82 [10.1K]

In point for (2,7) and in Equation form x=2 y=7

6 0

3 years ago

4 (x+2)=2 (x+3)+2 (x-1) answer?

vekshin1

$4(x+2)=2(x+3)+2(x-1)\\\\use\ the\ distributive\ property:\ a(b\pm c)=ab\pm ac\\\\(4)(x)+(4)(2)=(2)(x)+(2)(3)+(2)(x)-(2)(1)\\\\4x+8=2x+6+2x-2\ \ \ \ |simplify\\\\4x+8=(2x+2x)+(6-2)\\\\4x+8=4x+4\ \ \ \ |-4x\\\\8=4\ FALSE!!!\\\\Answer:\ NO\ SOLUTION\ (x\in\O)$

4 0

3 years ago