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3 years ago

Is the relationship between inches and feet a function?

Mathematics

1 answer:

elena55 [62]3 years ago

8 0

Yes it is a function

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Which fraction equals a repeating decimal

bezimeni [28]

Here are some Examples: :)

$\frac{2}{9}$ is 0.2222222222 and so on

$\frac{4}{9}$ is 0.4444444444 and so on

$\frac{7}{9}$ is 0.777777777 and so on

So it could be anything like 9 or 6 as long is its like this $\frac{9}{4}$
$\frac{6}{4}$

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3 years ago

Mr. Crawford’s 4th-Period math class I ready question

drek231 [11]

Answer:

yes

Step-by-step explanation:

yes

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3 years ago

Marc wants to guess how many marbles are in a box that has a height of 18 inches. He calculates that there are 32 marbles in a h

Rainbow [258]

So every 5 inches in height, there are 32 marbles. You want to know how many marbles there are per 18 inches in height.

$\frac{32}{5} = \frac{x}{18}$

To get from 5 to 18, you multiply by 3.6.

Do the same thing to the numerator; 32 × 3.6 = 115.2.

Since 0.2 marbles is no marbles, you round down.

There are 115 marbles in the box.

♡ Hope this helps! ♡

❀ 0ranges ❀

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3 years ago

John is planning a trip to Disneyland in Los Angeles, CA. He is leaving his house in Sacramento with a full tank of gas. The tab

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Do the reaction photosynthesis

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3 years ago

What is the solution to the system? 1. x-y + 2 z = -7<br> 2. y + z =1<br> 3. x-2 y - 3 z = 0

kvv77 [185]

You'd find this problem easier to understand and do if you'd please list the defining equations vertically and line up variables:

1. x - 1y + 2 z = -7

2. y + 1z = 1

3. x - 2 y - 3 z = 0 Now eliminate the line numbers:

x - 1y + 2 z = -7

1y + 1 z = 1

x - 2 y - 3 z = 0

Let's use the elimination method to eliminate variable z: Seeing that z = 1 - y, we transform the first equation into 1x - 1y + 2(1-y) = -7

and the third into x - 2y - 3(1-y) = 0.

Simplifying 1x - 1y + 2(1-y) = -7

and x - 2y - 3(1-y) = 0,

we get

1x - 2y - 3 + 3y) = 0 and 1x - 1y + 2 - 2y = -7

which in turn simplify to

1x + y = 3 and 1x - 3y = -9

Having eliminated the variable z, we now focus on eliminating x. Mult. the 1st equation by -1, obtaining -1x - 1y = -3. Add this result to 1x - 3y = -9:

0 - 4y = -12, which tells us that y = 3. Subbing 3 for y in 1x + 1y = 3 tells us that x = 0.

All we have left to determine is the vaue of z.

Borrowing Equation 3, from above, we get x - 2 y - 3 z = 0, and into this equation we substitute x = 0 and y = 3: 0 -2(3) - 3z = 0.

Thus, -3z = 6, and z = -2.

The solution set is (0, 3, -2). You should check this by substitution.

3 0

3 years ago