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VladimirAG [237]
3 years ago
15

Is the relationship between inches and feet a function?

Mathematics
1 answer:
elena55 [62]3 years ago
8 0
Yes it is a function
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“which expression is the factored form of x^2-7x+10?”
mafiozo [28]
(X-5)(x-2) here you go
4 0
4 years ago
A(t)=.892t^3-13.5t^2+22.3t+579 how to solve this
Minchanka [31]

Answer:

t = (5 ((446 sqrt(3188516012553) - 827891226)^(1/3) - 204292 (-1)^(2/3) (3/(413945613 - 223 sqrt(3188516012553)))^(1/3)))/(223 6^(2/3)) + 1125/223 or t = 1125/223 - (5 ((-2)^(1/3) (223 sqrt(3188516012553) - 413945613)^(1/3) - 204292 (-3/(413945613 - 223 sqrt(3188516012553)))^(1/3)))/(223 6^(2/3)) or t = 1125/223 - (5 ((827891226 - 446 sqrt(3188516012553))^(1/3) + 204292 (3/(413945613 - 223 sqrt(3188516012553)))^(1/3)))/(223 6^(2/3))

Step-by-step explanation:

Solve for t over the real numbers:

0.892 t^3 - 13.5 t^2 + 22.3 t + 579 = 0

0.892 t^3 - 13.5 t^2 + 22.3 t + 579 = (223 t^3)/250 - (27 t^2)/2 + (223 t)/10 + 579:

(223 t^3)/250 - (27 t^2)/2 + (223 t)/10 + 579 = 0

Bring (223 t^3)/250 - (27 t^2)/2 + (223 t)/10 + 579 together using the common denominator 250:

1/250 (223 t^3 - 3375 t^2 + 5575 t + 144750) = 0

Multiply both sides by 250:

223 t^3 - 3375 t^2 + 5575 t + 144750 = 0

Eliminate the quadratic term by substituting x = t - 1125/223:

144750 + 5575 (x + 1125/223) - 3375 (x + 1125/223)^2 + 223 (x + 1125/223)^3 = 0

Expand out terms of the left hand side:

223 x^3 - (2553650 x)/223 + 5749244625/49729 = 0

Divide both sides by 223:

x^3 - (2553650 x)/49729 + 5749244625/11089567 = 0

Change coordinates by substituting x = y + λ/y, where λ is a constant value that will be determined later:

5749244625/11089567 - (2553650 (y + λ/y))/49729 + (y + λ/y)^3 = 0

Multiply both sides by y^3 and collect in terms of y:

y^6 + y^4 (3 λ - 2553650/49729) + (5749244625 y^3)/11089567 + y^2 (3 λ^2 - (2553650 λ)/49729) + λ^3 = 0

Substitute λ = 2553650/149187 and then z = y^3, yielding a quadratic equation in the variable z:

z^2 + (5749244625 z)/11089567 + 16652679340752125000/3320419398682203 = 0

Find the positive solution to the quadratic equation:

z = (125 (223 sqrt(3188516012553) - 413945613))/199612206

Substitute back for z = y^3:

y^3 = (125 (223 sqrt(3188516012553) - 413945613))/199612206

Taking cube roots gives (5 (223 sqrt(3188516012553) - 413945613)^(1/3))/(223 2^(1/3) 3^(2/3)) times the third roots of unity:

y = (5 (223 sqrt(3188516012553) - 413945613)^(1/3))/(223 2^(1/3) 3^(2/3)) or y = -(5 (-1/2)^(1/3) (223 sqrt(3188516012553) - 413945613)^(1/3))/(223 3^(2/3)) or y = (5 (-1)^(2/3) (223 sqrt(3188516012553) - 413945613)^(1/3))/(223 2^(1/3) 3^(2/3))

Substitute each value of y into x = y + 2553650/(149187 y):

x = (5 ((223 sqrt(3188516012553) - 413945613)/2)^(1/3))/(223 3^(2/3)) - 510730/223 (-1)^(2/3) (2/(3 (413945613 - 223 sqrt(3188516012553))))^(1/3) or x = 510730/223 ((-2)/(3 (413945613 - 223 sqrt(3188516012553))))^(1/3) - (5 ((-1)/2)^(1/3) (223 sqrt(3188516012553) - 413945613)^(1/3))/(223 3^(2/3)) or x = (5 (-1)^(2/3) ((223 sqrt(3188516012553) - 413945613)/2)^(1/3))/(223 3^(2/3)) - 510730/223 (2/(3 (413945613 - 223 sqrt(3188516012553))))^(1/3)

Bring each solution to a common denominator and simplify:

x = (5 ((446 sqrt(3188516012553) - 827891226)^(1/3) - 204292 (-1)^(2/3) (3/(413945613 - 223 sqrt(3188516012553)))^(1/3)))/(223 6^(2/3)) or x = -(5 ((-2)^(1/3) (223 sqrt(3188516012553) - 413945613)^(1/3) - 204292 ((-3)/(413945613 - 223 sqrt(3188516012553)))^(1/3)))/(223 6^(2/3)) or x = -(5 ((827891226 - 446 sqrt(3188516012553))^(1/3) + 204292 (3/(413945613 - 223 sqrt(3188516012553)))^(1/3)))/(223 6^(2/3))

Substitute back for t = x + 1125/223:

Answer: t = (5 ((446 sqrt(3188516012553) - 827891226)^(1/3) - 204292 (-1)^(2/3) (3/(413945613 - 223 sqrt(3188516012553)))^(1/3)))/(223 6^(2/3)) + 1125/223 or t = 1125/223 - (5 ((-2)^(1/3) (223 sqrt(3188516012553) - 413945613)^(1/3) - 204292 (-3/(413945613 - 223 sqrt(3188516012553)))^(1/3)))/(223 6^(2/3)) or t = 1125/223 - (5 ((827891226 - 446 sqrt(3188516012553))^(1/3) + 204292 (3/(413945613 - 223 sqrt(3188516012553)))^(1/3)))/(223 6^(2/3))

6 0
4 years ago
X cubed plus 2x cubed NEED THIS ASAP
elena55 [62]
X^3+2x^2
hope this helps
5 0
3 years ago
Read 2 more answers
Gina will package the trail mix into single servings. To do this, she needs to know the total volume of 1 serving.
mafiozo [28]

Answer:

150 cups and batch is 1 cup

Step-by-step explanation:

The total amount of snack mix for one recipe would be. 1. 1. 1 ... servings is 150 cups, and 1 batch is 10 cups, then she will need to bake 15 batches.

36 pages.

7 0
3 years ago
Two numbers have these properties:
Elina [12.6K]

The two numbers are 12 and 30

Step-by-step explanation:

Let us revise the meaning of HCF (highest common factor) and LCM (least common multiple)

  • The highest common factor of two numbers is the largest whole number which is a factor of both, the HCF of 4 and 6 is 2 because the factors of 4 are 1, 2, 4 and the factors of 6 are 1, 2, 3, 6; the common factors are 1, 2 and the greatest is 2 so the highest common factor of 4 , 6 is 2
  • The least common multiple of two numbers is the smallest number that they both divide evenly into, the least common multiple of 4 and 6 is 12 because the multiples of 4 are 4, 8, 12, 16, ... and the multiples of 6 are 6, 12, 18, 24, ...; the first common multiple between then is 12

∵ Both numbers are greater than 6

∵ Their HCF is 6

- That means 6 is a factor of both of them

∴ The two numbers are multiple of 6 without any other common

   factor greater than 6

Let us write the multiple of 6 greater than 6

∵ 12 , 18 , 24 , 30 , 36 , ......... are multiples of 6

∵ Their LCM is 60

- That means 60 can divided by them

∵ 60 can divided by 12

∵ 60 can divided by 30

∵ The factors of 12 are 1 , 2 , 3 , 4 , 6 , 12

∵ The factor of 30 are 1 , 2 , 3 , 5 , 6 , 10 , 15 , 30

∵ Their common factors are 1 , 2 , 3 , 6 and the greatest one is 6

- 12 and 30 have HCF of 6 and LCM of 60

∴ The two numbers are 12 and 30

The two numbers are 12 and 30

Learn more:

You can learn more about the factors in brainly.com/question/5194236

#LearnwithBrainly

4 0
4 years ago
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