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2 years ago

8

Estimate the moment of inertia of a bicycle wheel 72 cm in diameter. The rim and tire have a combined mass of 1.4 kg . The mass

of the hub can be ignored. Express your answer to two significant figures and include the appropriate units.

1 answer:

asambeis [7]2 years ago

7 0

Answer:

0.18 kg.m²

Step-by-step explanation:

Moment of Inertia (I) = m r²----------------------------------------------------------- (1)

Where

m= mass of the rim and tire

r = radius

I = mr²----------------------------------------------------------------------- (2)

m =1.4kg

r =72/2

= 36cm

= 0.36 m

Substituting into (2), we have :

I = 1.4 x(0.36)²

= 0.18144‬

≈ 0.18 kg.m²

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Step-by-step explanation:

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This can also be written as :

$\sqrt{6x.15xy.20}$

= $\sqrt{1800x^{2}y}$

which could be written as :

$\sqrt{900x^{2}}$ x $\sqrt{2y}$

= 30x $\sqrt{2y}$

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2 years ago

Amber has 36 smarties to share among herself and 3 friends. How many smarties will each of them Receive?

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2 years ago

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liubo4ka [24]

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3 years ago

Nina decided to raise money for a community organization that provides free classes and legal

Over [174]

A percentage is a way to describe a part of a whole. The money that is raised by Nina in the second month is $960.

<h3>What are Percentages?</h3>

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1 year ago

If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?

enyata [817]

Step-by-step explanation:

$\bf➤ \underline{Given-} \\$

$\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\$

$\bf➤ \underline{To\: find-} \\$

$\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\$

$\bf ➤\underline{Solution-} \\$

<u>Let us assume that:</u>

$\rm: \longmapsto u = {x}^{2013}$

<u>Therefore, the equation becomes:</u>

$\rm: \longmapsto u + \dfrac{1}{u} = 2$

$\rm: \longmapsto \dfrac{ {u}^{2} + 1}{u} = 2$

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$\rm: \longmapsto{u}^{2} - 2u + 1 =0$

$\rm: \longmapsto {(u - 1)}^{2} =0$

$\rm: \longmapsto u = 1$

<u>Now substitute the value of u. We get:</u>

$\rm: \longmapsto {x}^{2013} = 1$

$\rm: \longmapsto x = 1$

<u>Therefore:</u>

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 1 + 1$

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★ <u>Which is our required answer.</u>

$\textsf{\large{\underline{More To Know}:}}$

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

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2 years ago