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erica [24]
3 years ago
8

Estimate the moment of inertia of a bicycle wheel 72 cm in diameter. The rim and tire have a combined mass of 1.4 kg . The mass

of the hub can be ignored. Express your answer to two significant figures and include the appropriate units.
Mathematics
1 answer:
asambeis [7]3 years ago
7 0

Answer:

0.18 kg.m²

Step-by-step explanation:

Moment of Inertia (I) = m r²----------------------------------------------------------- (1)

Where

m= mass of the rim and tire

r = radius

I = mr²----------------------------------------------------------------------- (2)

m =1.4kg

r =72/2

 = 36cm

 = 0.36 m

Substituting into (2), we have :

I = 1.4  x(0.36)²

 = 0.18144‬

≈ 0.18 kg.m²

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the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

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\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

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\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

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Answer:

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