Thanks for sitting tight. Answers in attachment below.
*Percentages are close approximations to the probabilities. Ideally, the fractions should be used.
I would say A or C
dont take my word for it tho idk
Answer:
y=2
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable. Hope this helps!
Answer:
a) bb, bg, gb, gg
b) 25% probability of getting two green dash eyed children.
c) 50% probability of getting exactly one blue dash eyed child and one green dash eyed child.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this question:
Total of eight outcomes.
a. Construct a similar sample space for the possible eye color outcomes (using b for blue dash eyed and g for green dash eyed) of two children.
bb, bg, gb, gg
b. Assuming that the outcomes listed in part (a) were equally likely, find the probability of getting two green dash eyed children.
Four outcomes.
Of those, in one(gg), you get two green dash eyed children.
1/4 = 0.25
25% probability of getting two green dash eyed children.
c. Find the probability of getting exactly one blue dash eyed child and one green dash eyed child.
In two of those(bg and gb) you get one blue dash eyed child and one green dash eyed child.
2/4 = 0.5
50% probability of getting exactly one blue dash eyed child and one green dash eyed child.
