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masha68 [24]
3 years ago
11

How can you determine if a piece-wise relation is a function?

Mathematics
1 answer:
uysha [10]3 years ago
7 0
Use the vertical line rule to test. 
Imagine you are drawing lines parallel to the y axis, if any of your lines touches the graph twice, the graph does not represent a function. otherwise, it does. 
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A vector is used to express a car's change in position, or displacement, by tracking its motion over a large area defined by a c
Mnenie [13.5K]

Answer:

The correct answer is option C: (8, 14).

Step-by-step explanation:

The car's displacement in vector form can be found by subtracting the initial points from the final points.    

Initial: (x₁, y₁) = (-3, -5)

Final: (x₂, y₂) = (5, 9)          

For the x-coordinate, we have:  

d_{x} = x_{2} - x_{1} = 5 - (-3) = 8

And for the y-coordinate, we have:

d_{y} = y_{2} - y_{1} = 9 - (-5) = 14

The car's displacement in vector form is:

d = (d_{x}, d_{y}) = (8, 14)  

Therefore, the correct answer is option C: (8, 14).

I hope it helps you!                        

7 0
3 years ago
Help me out a little
konstantin123 [22]
I believe your answer is (1,5)

I graphed the equations and the ordered pairs and (1,5) is the only point that fell on both of the shaded areas.

hope this helps !!
8 0
3 years ago
Suppose you flip a coin five times.
hoa [83]
The answer would be A, since the occurance is based purely on chance
4 0
4 years ago
Read 2 more answers
Steve bought a new graduated cylinder for his chemistry class.It holds 1,058.75 of liquid. If the cylinder has a radius of 5.5 c
patriot [66]

Answer:

35 cm

Step-by-step explanation:

volume of cylinder = πr²h

πr²h = 1058.75π

Divide both sides by π.

r²h = 1058.75 cm³

r = 5.5 cm

Substitute r² with (5.5 cm)².

(5.5 cm)²h = 1058.75 cm³

h = 1058.75/30.25 cm

h = 35 cm

4 0
3 years ago
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xz_007 [3.2K]

Answer:

y = 10x

Step-by-step explanation:

y = amount earned

x = time ( hours )

so lets say she earns $40

40 = 10x

divide by 10 you get

x = 4

she worked for 4 hours

You can use this equation for any amount of time.

7 0
4 years ago
Read 2 more answers
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