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ludmilkaskok [199]
3 years ago
8

Which of the following uses absolute value correctly to show the distance between-20 and 14

Mathematics
1 answer:
LiRa [457]3 years ago
4 0
The answer is 14 because it is a positive
You might be interested in
Answer with the explanation step by step
andrey2020 [161]

Answer:

The answer is A. \frac{3(x-21)}{(x+7)(x-7)}.

Step-by-step explanation:

To find the difference of this problem, start by simplifying the denominator, which will look like \frac{3}{x+7}-\frac{42}{(x+7)(x-7)}. Next, multiply \frac{3}{x+7} by \frac{x-7}{x-7}  to create a fraction with a common denominator in order to subtract from \frac{42}{(x+7)(x-7)}. The problem will now look like \frac{3}{x+7}*\frac{x-7}{x-7}-\frac{42}{(x+7)(x-7)}.  

Then, simplify the terms in the problem by first multiplying \frac{3}{x+7} and \frac{x-7}{x-7}, which will look like \frac{3(x-7)}{(x+7)(x-7)}-\frac{42}{(x+7)(x-7)}. The next step is to combine the numerators over the common denominator, which will look like \frac{3(x-7)-42}{(x+7)(x-7)}.

Next, simplify the numerator, and to simplify the numerator start by factoring 3 out of 3(x-7)-42, which will look like \frac{3(x-7-14)}{(x+7)(x-7)}. Then, subtract 14 from -7, which will look like \frac{3(x-21)}{(x+7)(x-7)}. The final answer will be \frac{3(x-21)}{(x+7)(x-7)}.    

4 0
3 years ago
A sum of 17 and a difference 3
sleet_krkn [62]
It would be 9-6=3 and 9+6=17 hope this help
6 0
3 years ago
Read 2 more answers
Which is the more reasonable measurement of the distance between the tracks on a DVD: 7.4 ⋅ 10−4 mm or 7.4 ⋅ 104 mm? Justify you
EleoNora [17]

Answer:

A- 7.4 ⋅ 10−4 mm

Step-by-step explanation:

Well, to solve this problem, we must convert the number and / or the units in a more imaginable one.

We are given two choices:

a. 7.4 x 10^-4 mm

b. 7.4 x 10^4 mm

Converting the units and numbers into meters and general form, respectively. (What is meant by general form is not to write it in scientific notation).

a. 7.4 x 10^-4 mm (1 m / 1000 mm) = 0.00000074 m

b. 7.4 x 10^4 mm (1 m / 1000 mm) = 74 m

Now comparing the two values above, what do you think is the distance between the tracks on a DVD? Definitely NOT 74 m or else the DVD is extremely big. Therefore the correct is the smaller one.

8 0
2 years ago
Read 2 more answers
Consider a TV set that consumes 120 W of electric power when it is on, and is kept on for an average of 6 h per day. For a unit
Andru [333]

The cost of electricity consumed by the TV per month is <u>$4.968</u>.

In the question, we are given that a TV set consumes 120W of electric power when switched on. It is kept on for a daily average of 6 hours per day. The number of days in the month is given to be 30 days. The cost per unit of electricity is 23 cents per kWh.

We are asked to find the cost of electricity the TV consumes in the month.

The daily energy consumed by the TV = Power*Daily time = 120*6 Wh = 720 Wh.

The monthly energy consumed by the TV = Daily energy*Number of days in the month = 720*30 Wh = 21600 Wh = 21600/1000 kWh = 21.6 kWh.

Hence, the total cost of electricity the TV consumes = Monthly energy*Per unit cost = 21.6*23 cents = 496.8 cents = $496.8/100 = $4.968.

Therefore, the cost of electricity consumed by the TV per month is <u>$4.968</u>.

Learn more about computing costs at

brainly.com/question/14277272

#SPJ4

3 0
2 years ago
Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
sasho [114]

Answer:

a) P(X

P(z

b) P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)

P(z>1.47)=1-P(z

c)  P(3

P(-0.882

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

X \sim N(4.5,1.7)  

Where \mu=4.5 and \sigma=1.7

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table:

P(z

Part b

We are interested on this probability

P(X>3.0)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)

And we can find this probability using excel or the normal standard table:

P(z>1.47)=1-P(z

Part c

P(3

And we can find this probability using excel or the normal standard table liek this:

P(-0.882

3 0
3 years ago
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