Answer:
The first is equation the second is expression the third is expression and the fourth is equation
Step-by-step explanation:
equations have equal signs and expressions dont
Answer:
Lowest score needed=4.92
Step-by-step explanation:
Using the standard normal distribution table we find the value of standard normal deviate corresponding to area of 15%
For area of 15% we have Z= -1.04
Thus we have
Applying values we get
Thus lowest score needed = 4.92
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
___________________________________________
If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
9514 1404 393
Answer:
12.0 cm
Step-by-step explanation:
The Pythagorean theorem applies:
(12 cm)² +b² = (17 cm)²
b² = (289 -144) cm² = 145 cm²
b = √145 cm ≈ 12.04 cm
b ≈ 12.0 cm . . . . rounded to 1 decimal place
