Anyone know this one?
1 answer:
You might be interested in
Assuming the coin is fair, the probability of the coin toss resulting in H is 
. So the probability of getting two Hs, in any order, is
Answer:
The probability of flipping Heads at least once is .
Step-by-step explanation:
The probability of an event, say <em>E</em>, is the ratio of the favorable outcomes to the total number of outcomes, i.e.
The sample space of flipping two coins is:
S = {HH, HT, TH and TH}
Total number of outcomes = 4
Compute the probability of flipping Heads at least once as follows:
Let <em>X</em> = heads.
P (X ≥ 1) = P (X = 1) + P (X = 2)
Thus, the probability of flipping Heads at least once is .
The experiment of flipping a coin is a binomial experiment.
Since there are only two outcomes of the experiment, either a Heads or a Tails.
So if <em>X</em> is defined as the number of heads in <em>n</em> flips of a coin then the random variable <em>X</em> follows a binomial distribution with probability <em>p = 0.5</em> of success.