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zmey [24]
3 years ago
8

The price of oil decreased from $52 per barrel to $48 per barrel. What is the percentage decrease in the price of oil? Round you

r answer to the nearest tenth of a percent.
Mathematics
1 answer:
zaharov [31]3 years ago
7 0

Answer:

7.7%

Step-by-step explanation:

Given that,

The price of oil decreased from $52 per barrel to $48 per barrel.

We need to find the percentage decrease in the price of oil. It can be calculated as follows :

\%=\dfrac{52-48}{52}\times 100\\\\=7.69\%

or

= 7.7%

So, the percentage decrease in the price of oil is 7.7%.

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A membership to LA Fitness is on sale for $ 112 50. That represents
RSB [31]

Answer:

Step-by-step explanation:

let the original price be x

discount is 25%, .25x

discounted price x-.25x=.75x

112.50=.75x

x=150 was the membership selling before the discount

5 0
2 years ago
Help me out :) 15 points! Show work, and only answer if you know how to do it correctly.
Volgvan

Answer:

28

Step-by-step explanation:

First u have to find the bisector,then u have to descrese 18

8 0
3 years ago
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
2 years ago
g(x)=2x+9g, left parenthesis, x, right parenthesis, equals, 2, x, plus, 9 g ( g(g, left parenthesis ) = 15 )=15right parenthesis
Dmitriy789 [7]

Answer:

I don't understand your question

6 0
3 years ago
Read 2 more answers
Do you know the value of x?
inysia [295]

Answer:

im not sure but i think it is -7

Step-by-step explanation:

i think so just because looking at the top example but i might be wrong

8 0
3 years ago
Read 2 more answers
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