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3 years ago

Please give me a cool title to give my electromagnetic project.

Mathematics

2 answers:

CaHeK987 [17]3 years ago

8 0

Answer:

these may sound lame,but......

"Electricity in action"

"Electric frequents"

"How an electromagnetic field works"

"how an electromagnetic object works"

"electrified waves"

There you go!

Mkey [24]3 years ago

4 0

Magnetic power and then u can do like bold hehe

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Under the last-in, first-out (LIFO) inventory valuation method, a price index for inventory must be established for tax purposes

frosja888 [35]

Answer:

The laspeyres method of weighted aggregate price index is used of LIFO inventory valuation, therefore laspeyres index number is 106.08

Step-by-step explanation:

First of all we would have to perform the following table:

Product Ending Inventory(Q0) Begining(P0) Ending(P1) P0×Q0 P1×Q0

A 500 0.15 0.21 75 105

B 50 1.60 1.80 80 90

C 100 4.50 4.20 450 420

D 40 12.00 13.40 480 536

Total 1085 1151

Therefore, using laspeyres index number, we calculate the following:

laspeyres index number=(∑P1×Q0/∑P0×Q0)×100

laspeyres index number=(1151/1085)×100

laspeyres index number=106.08

8 0

3 years ago

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$