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Nookie1986 [14]
3 years ago
5

Please give me a cool title to give my electromagnetic project.

Mathematics
2 answers:
CaHeK987 [17]3 years ago
8 0

Answer:

these may sound lame,but......

"Electricity in action"

"Electric frequents"

"How an electromagnetic field works"

"how an electromagnetic object works"

"electrified waves"

There you go!

Mkey [24]3 years ago
4 0
Magnetic power and then u can do like bold hehe
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when inches are converted to centimeters, is the number of centimeters greater than the number of inches?
Gnom [1K]
Yes, because centimeters are smaller than inches, making you need more of them to equal an inch. 
4 0
3 years ago
How do I start this problem? I don't need help with the graphing part.
tamaranim1 [39]

Answer:

x = 6 , y = 0   (x , y) = (6 , 0)

x = 12, y = 3   (x , y) = (12 , 3)

x = 24, y = 9   (x , y) = (24 , 9)

Step-by-step explanation:

Simply plug in a x, and find a y that would make the equation true:

When x = 6:

6 - 2y = 6

6 (-6) - 2y = 6 (-6)

-2y = 0

(-2y)/-2 = (0)/-2

y = 0

When x = 6, y = 0    (x , y) = (6 , 0)

When x = 12:

12 - 2y = 6

12 (-12) -2y = 6 (-12)

-2y = -6

(-2y)/-2 = (-6)/-2

y = 3

When x = 12, y = 3   (x , y) = (12 , 3)

When x = 24:

24 - 2y = 6

24 (-24) - 2y = 6 (-24)

-2y = -18

(-2y)/-2 = (-18)/-2

y = 9

When x = 24, y = 9   (x , y) = (24 , 9)

~

3 0
3 years ago
F(x)= square root of x+2; g(x)=8x-12<br> find f(g(x))
Ann [662]
f(x)=\sqrt{x+2}\\g(x)=8x-12\\f(g(x))=\sqrt{8x-12+2}=\sqrt{8x-10}

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B0.0001%7D%20-%5Csqrt%5B5%5D%7B0.00032%7D" id="TexFormula1" title="\sqrt[4]{0.
Dmitry_Shevchenko [17]

Hi!-0.041511 is the answer.

6 0
2 years ago
You should solve the answer for z not m pls
mariarad [96]

Step-by-step explanation:

we can factor out z

so that'll be

z((1/m)-(1/n))=1

divide by the value in parentheses on both sides

z=1/((1/m)-(1/n))

I can't tell if there's more the problem wants you to do. I could rewrite the equation on paper more easily, but I don't have one on hand

5 0
2 years ago
Read 2 more answers
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