The intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .
<h3>
What is magnitude of earthquake
?</h3>
Magnitude of earthquake is the measure of the size of origin of the earthquake. The magnitude of the earthquake keeps the same value for each place.
An earthquake with a magnitude of about 2. 0 or less is called a micro-earthquake and not felt usually.The intensity of an earthquake with a magnitude of 2.
Let the intensity of this earthquake is <em>n </em>times greater than the intensity of an a standard earthquake. Thus the intensity of standard earthquake can be given as,
If the magnitude would be 3 then the intensity would be,
It would be 1000 times greater than the standard earthquake and so on.
Thus, the intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .
Learn more about the magnitude of earthquake here;
brainly.com/question/18109453
A right angle triangle normally relates to Pythagoras Theorem , and this is related to the hypotenuse, the answer maybe the hypotenuse. As the other sides are the opposite and alternative
Answer:
a) P(X=2)= 0.29
b) P(X<2)= 0.59
c) P(X≤2)= 0.88
d) P(X>2)= 0.12
e) P(X=1 or X=4)= 0.24
f) P(1≤X≤4)= 0.59
Step-by-step explanation:
a) P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4)= 1-0.41-0.18-0.06-0.06= 0.29
b) P(X<2)= P(X=0) + P(X=1)= 0.41 + 0.18 = 0.59
c) P(X≤2)= P(X=0) + P(X=1) + P(X=2)=0.41+0.18+0.29= 0.88
d) P(X>2)=P(X=3) + P(X=4)=0.06+0.06= 0.12
e) P(X=1 or X=4)=P(X=1 ∪ X=4) = P(X=1) + P(X=4)=0.18+0.06= 0.24
f) P(1≤X≤4)=P(X=1) + P(X=2) + P(X=3) + P(X=4)=0.18+0.29+0.06+0.06= 0.59
the answer is y=4x-11
use y+1=4x-12
move 1 to negative because move to the other side
so the answer is y=4x-11
Answer:
x = 0, 51
Step-by-step explanation:
<u>→First, you need to factor out the GCF (Greatest Common Factor), which is -0.03x, like so:</u>
-0.03x (x - 51) = 0
<u>→Remove the -0.03 by divide it by both sides:</u>
x(x - 51) = 0
<u>→Separate each, like so:</u>
x = 0
x - 51 = 0
<u>→Solve for x:</u>
x - 51 = 0
x = 51
<u>Your solutions are, 0 and 51.</u>
