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Gnoma [55]
3 years ago
6

How can you tell the difference between additive comparison and multiplicative comparison?

Mathematics
1 answer:
Ann [662]3 years ago
4 0
When you are adding you are ,say you have the number 4 and you need to add it to 5 you are basically mushing those two numbers together and seeing what you get, and I got 9. with multiplying you are multiplying it by itself however many times you need to, to find out the answer. :)
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Now assume this holds in general for n=k, i.e. that 2^k>k. We want to prove the statement then must hold for n=k+1.

Because 2^k>k, you have

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2k>k+1

for k>1. Well this is obviously true, because solving the inequality gives 3k>1\implies k>\dfrac13. So you're done.

If you n is any real number, you can use derivatives to show that 2^n increases monotonically and faster than n.
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