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Anna11 [10]
3 years ago
8

If a data value in a normal distribution has a negative z-score, which of the following must be true?

Mathematics
2 answers:
Naily [24]3 years ago
6 0

Answer:

The data value must be less than the mean.

Step-by-step explanation:

mel-nik [20]3 years ago
4 0
Correct Answer:
The data value must be less than the mean.

The formula for the z value is:

z-value = (Data value - Mean) / Standard Deviation

The z-value will be negative when the Numerator of the above expression will be negative. The numerator will be negative only when the Data Value is less than the mean value. For example, for a data value of 5 and mean value 8, the numerator will be -3, and when it will be divided by standard deviation, the resulting z value will be negative.

So, Third option is the correct answer. 
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Yoko is buying a car from a local car dealership. She wants to get the lowest interest rate possible. Which will most likely hel
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Answer:

B)making sure she has a positive credit history

Step-by-step explanation:

Yoko is buying a car from a local car dealership. She wants to get the lowest interest rate possible.

B) making sure she has a positive credit history - will most likely help her get the lowest interest rate.

Getting low interest rates does not depend on the way you talk or if you have a driver licence.

It depends on your previous credit history and credit scores. When you have good scores, this means you have always paid your debts on time and this makes sure that you will do the same in future.

So, you get low interest rates based on good credit history.

8 0
3 years ago
Read 2 more answers
Help pls, will mark brainliest
BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be {\sf T_n} is given by ;

  • {\boxed{\bf T_{n}=T_{1}+(n-1)d}}

Where , <u>d</u> is the common difference

Now , here we are given with ;

{\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

{: \implies \quad \sf T_{1}+(5-1)d=T_{5}}

Putting the values and transposing 1st term to RHS , we have ;

{: \implies \quad \sf 4d = -4-8}

{: \implies \quad \sf d=-\dfrac{12}{4}}

{: \implies \quad \sf d=-3}

Now , as we got the common difference , so we can find out the missing terms now ;

{: \implies \quad \sf T_{2}= T_{1}+(2-1)d}

{: \implies \quad \sf T_{2}= 8 +d}

{: \implies \quad \sf T_{2}= 8-3}

{: \implies \quad \bf \therefore \:  T_{2}= 5}

Now

{: \implies \quad \sf T_{3}= T_{1}+(3-1)d}

{: \implies \quad \sf T_{3}= 8 +2d}

{: \implies \quad \sf T_{3}= 8-6}

{: \implies \quad \bf \therefore \:  T_{3}= 2}

Also ,

{: \implies \quad \sf T_{4}= T_{1}+(4-1)d}

{: \implies \quad \sf T_{4}= 8 +3d}

{: \implies \quad \sf T_{4}= 8-9}

{: \implies \quad \bf \therefore \:  T_{4}= -1}

Now , The given table can be written as ;

{\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

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Answer:

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What the perimeter is ?
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Answer:

the perimeter is the total length of that plane figure

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A (−1,4) maps into A′ (2,−1). Find the translation rule
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its on quizlet

Step-by-step explanation:

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