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igor_vitrenko [27]
3 years ago
14

614 times 4.0 must show work

Mathematics
2 answers:
lana [24]3 years ago
4 0
614 + 614 + 614 +614 = 2,456
So that means
614 times 4 is 2,456
Elanso [62]3 years ago
3 0

Answer:

2456

Step-by-step explanation:

614×4.0 srry if I got it wrong

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The tank at a gas station contained 400 gallons of gas. A tanker truck that contained 8,100 gallons of gas filled the station's
spin [16.1K]

Answer:

1300

Step-by-step explanation:

Let the amount put in the station's tank = x

4(400 + x) = 8100 - x                           Remove the brackets

1600 + 4x = 8100 - x                            Subtract 1600 from both sides

1600 - 1600 + 4x = 8100 - 1600 - x     Do the subtraction

4x = 6500 - x                                        Add x to both sides

4x + x = 6500 - x + x        

5x = 6500                                            Divide by 5

5x/5 = 6500/5                                      

x = 1300

1300 gallons were added to the station's tank.

3 0
3 years ago
Read 2 more answers
Jonathan purchased 4 shirts, 2 jackets, and 3 pants. How many different outfits using a
vagabundo [1.1K]

Answer:

24 way im pretty sure

Step-by-step explanation:

4 0
3 years ago
Hey! i’ll give brainliest please help
gizmo_the_mogwai [7]
A women doesn’t feel right about ditching school is an internal struggle
3 0
3 years ago
If there were 80 points scored overall, how many of them were scored by Bridgette? she scored 5% of the points
Simora [160]

Answer: she scored 4 points

Step-by-step explanation: 5% of 80=4

;-----------;

6 0
3 years ago
Read 2 more answers
If x^3 + 1/x^3 = 110 then find x + 1/x
Svetlanka [38]
Use:(a+b)^3=a^3+3a^2b+3ab^2+b^3\ (*)\\\\x^3+\left(\dfrac{1}{x}\right)^3\\=\underbrace{x^3+3\cdot x^2\cdot\dfrac{1}{x}+3\cdot x\cdot\left(\dfrac{1}{x}\right)^2+\left(\dfrac{1}{x}\right)^3}_{(*)}-3\cdot x^2\cdot\dfrac{1}{x}-3\cdot x\cdot\left(\dfrac{1}{x}\right)^2\\\\=\left(x+\dfrac{1}{x}\right)^3-3x-3\cdot\dfrac{1}{x}=\left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)

therefore

x^3+\left(\dfrac{1}{x}\right)^3=110\iff \left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)=110\\\\subtitute\ t=x+\dfrac{1}{x}\\\\t^3-3t=110\ \ \ \ |subtract\ 110\ from\ both\ sides\\\\t^3-3t-110=0\\\\t^3-25t+22t-110=0\\\\t(t^2-25)+22(t-5)=0\ \ \ |use\ a^2-b^2=(a-b)(a+b)\\\\t(t-5)(t+5)+22(t-5)=0\\\\(t-5)[t(t+5)+22]=0\iff t-5=0\ or\ \underbrace{t^2+5t+22=0}_{no\ solution}\\\\t=5\iff x+\dfrac{1}{x}=5\\\\Answer:\boxed{x+\dfrac{1}{x}=5}
3 0
3 years ago
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