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Artist 52 [7]
4 years ago
12

Graph the function. Thanks.

Mathematics
1 answer:
KengaRu [80]4 years ago
3 0
That should be about right

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Ms. Miller wants to give each of her students 1/4 of a pound of modeling clay. She has 26 students. How many pounds of modeling
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26 * 1/4 =6.5

The answer would be B.
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3 years ago
Mary is selling chocolate bars to raise money. She earns $3 for each solid milk chocolate bar sold and $4 for each caramel-fille
m_a_m_a [10]

Answer:

3m + 4c

Step-by-step explanation:

Whenever a word problem says the word earn that means the slope, also known as the rate of change, will be positive. Knowing this you can determine that both the caramel and milk chocolate slopes will be positive. After figuring all that out the only thing left to do is to make the equation. You know you have two slopes, and each slope needs a variable, so you will have to look back at the question. It is given that m represents the milk chocolate and c represents the caramel. Now all you have to do is make the slope the coefficient to the corresponding variable. The milk chocolates are 3 dollars, so the 3 goes in front of the m and the caramel chocolates are 4 dollars, so teh 4 goes in front of the 4. Since both slopes are positive no negatives or minus signs will be used in the equation. Knowing all this information you can now create the expression 3m + 4c.

6 0
3 years ago
Is -1/4 a rational number
pav-90 [236]

Answer:

Yes.

Step-by-step explanation:

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3 years ago
The product of 576 and 684 is irrational or rational
umka2103 [35]

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Read 2 more answers
USING the Midpoint Formula , POINT A is at (-3,-5) and point M is at (-0.5,0). what are the coordinates of point B
Rasek [7]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x-3}{2}~~,~~\cfrac{y-5}{2} \right)~~=~~\stackrel{\stackrel{Midpoint}{M}}{(-0.5~,~0)}\implies \begin{cases} \cfrac{x-3}{2}=-0.5\\[1em] x-3=-1\\ \boxed{x= 2}\\ \cline{1-1} \cfrac{y-5}{2}=0\\[1em] y-5=0\\ \boxed{y=5} \end{cases}

7 0
3 years ago
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