Its pretty hard what can I do to get help

Noor loves going to the theater and discussing each play in detail with her friends. She thinks she’d like a career as a theater

ollegr [7]

Answer:depends on if she want her viewers to laugh love or cry

Explanation:

6 0

3 years ago

Read 2 more answers

Which set of lines in this excerpt from "easter, 1816" by w. b. yeats suggests that the speaker had only a limited acquaintance

ExtremeBDS [4]

Answer:

Option #1:

I have passed with a nod of the head

Or polite meaningless words,

Or have lingered awhile and said

Polite meaningless words,

Prompt:

Select the correct text in the passage.

Which set of lines in this excerpt from "Easter, 1816" by W. B. Yeats suggests that the speaker had only a limited acquaintance with the people he is writing about?

I have met them at close of day

Coming with vivid faces

From counter or desk among grey

Eighteenth-century houses.

[Option #1:] I have passed with a nod of the head

Or polite meaningless words,

Or have lingered awhile and said

Polite meaningless words,

And thought before I had done

Of a mocking tale or a gibe

To please a companion

Around the fire at the club,

[Option #2:] Being certain that they and I

But lived where motley is worn:

All changed, changed utterly:

A terrible beauty is born.

. . .

[Option #3:] Hearts with one purpose alone

Through summer and winter seem

Enchanted to a stone

To trouble the living stream.

Commentary: I hope that this helps you. The Lord bless you and keep you, my friend. Shalom

8 0

2 years ago

If you know slipknot name one song and ill do all your work

Elena L [17]

Answer:

Spit it out

Explanation:

Best song so far, Im new to the slipknot fandom

6 0

2 years ago

For 2-methylbutane, the ∆h° of vaporization is 25. 22 kj/mol and the ∆s° of vaporization is 84. 48 j/mol･k. At 1. 00 atm and 201

pogonyaev

The Gibbs free energy ΔG for the vaporisation of 2-methylbutane, in KJ/mol is 8.24 KJ/mol

<h3>Data obtained from the question </h3>

Enthalpy change (ΔH) = 25. 22 KJ/mol
Change in entropy (ΔS) = 84.48 J/Kmol = 84.48 / 1000 = 8.448×10¯² KJ/Kmol
Temperature (T) = 201 K

Gibbs free energy (ΔG) =?

<h3>How to determine the Gibbs free energy </h3>

The Gibbs free energy for the reaction can be obtained as follow:

ΔG = ΔH – TΔS

ΔG = 25.22 – (201 × 8.448×10¯²)

ΔG = 25.22 – 169.8048

ΔG = 8.24 KJ/mol

Thus, the ΔG for the reaction is 8.24 KJ/mol

Learn more about Gibbs free energy:

brainly.com/question/9552459

7 0

3 years ago

The solution to 3x2 – 12x 24 = 0 is .

kupik [55]

Answer:

-9x28=0

Explanation:

4 0

3 years ago