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4 years ago

Help please algebra 8th grade need to finish ASAP!!

Mathematics

1 answer:

Trava [24]4 years ago

3 0

3/3 I THIB=NKKKKKKKKKKKKKKKKKKKKKKKKK

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Paul is running Tennis shop. He sells balls and rackets. Rackets (R) cost $1.20 each and Balls (B) cost $2:0 each. At the end of

Rus_ich [418]

The system of equations that represent the situation are 1.20R + 2B = 70, and R + B = 90.

<h3>What are the system of equations?</h3>

The system of equations are sets of equations that have to be solved simultaneously in order to determine their required values. They are often referred to as simultaneous equations.

To learn more about simultaneous equations, please check: brainly.com/question/25875552

8 0

2 years ago

A chocolate maker melts three blocks of chocolate weighing 5.4 ounces, 6.1 ounces, and 5.7 ounces. If

Nady [450]

Answer:

43 truffles

Step-by-step explanation:

First add all of the weights together

5.4+6.1+5.7=17.2

Divide the total chocolate by the weight of a truffle

17.2/0.4=43

4 0

3 years ago

emelia earns $8.74 per hour plus a gas allowence of $3.50 per day at her job how much does Emelia jobs pays in a day when she wo

trapecia [35]

Answer:

8.74 (3.50) + 3.50

= $51.57

Step-by-step explanation:

8 0

2 years ago

Write all the factors of 27.<br> Use commas to separate them.

UkoKoshka [18]

Answer:

1,3,9,27

Step-by-step explanation:

5 0

3 years ago

We measure the diameters for a random sample of 25 oak trees in a neighbourhood. Diameters of oak trees in the neighbourhood fol

jarptica [38.1K]

Answer:

The required confidence inteval = 94.9%.

Step-by-step explanation:

Confidence interval: Mean ± Margin of error

Given: A confidence interval for the true mean diameter of all oak trees in the neighbourhood is calculated to be (36.191, 42.969).

i.e. Mean + Margin of error = 42.969 (i)

Mean - Margin of error = 36.191 (ii)

Adding (i) and (ii), we get

$2Mean =79.16\\\\\Rightarrow\ Mean= 39.58$

Margin of error = 42.969-39.58 [from (i)]

= 3.389

Margin of error = $t^* \dfrac{\sigma}{\sqrt{n}}$

here n= 25 $, \ \sigma=8.25$

i.e.

$3.389=t^*\dfrac{8.25}{5}\\\\\Rightarrow\ t^* = \dfrac{3.389}{1.65}\\\\\Rightarrow\ t^* =2.0539 \$

Using excel function 1-TDIST.2T(2.054,24)

The required confidence inteval = 94.9%.

7 0

3 years ago