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marissa [1.9K]
3 years ago
9

Uhm I have no idea how to answer this I’ve been trying for the past like 3 days

Mathematics
2 answers:
ycow [4]3 years ago
5 0
................................
Svet_ta [14]3 years ago
3 0
(Aren't two column proofs the best? I used to shred a paper when a question asked me to write proof, back in Geometry class)

So I assume the check mark mean you got that part correct. For the first statement, it should be correct, and I don't know why it isn't marked right. 

Step three is basically the same exact thing as step two, so perhaps, don't add that step. 

For me, the question is asking something that is so simple, that it could be solved with basic LOGIC. 

However, since its asking us to write a "proof," here's my "fabulous" two column proof:

<ABC = <DEF - Given
<GHI = <DEF - Given
<ABC = GHI - Transitive property.

Overall, I have really negative feelings toward proofs because most of the time, the use of all these stupid theorems and postulates is dumb.
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Mary would like to buy a laptop computer with an original price of $964.60. Which coupon should she use? 50 % off or save $400.0
soldi70 [24.7K]
She should use 50% off.

964 divided by 1/2 = $482

964 - 400 = $564
3 0
3 years ago
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If the endpoints of the diameter of a circle are (6, 3) and (2, 1), what is the standard form equation of the circle?
Anastasy [175]
If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:

(x,y)=((6+2)/2, (3+1)/2)=(4,2)

Now we need to find the radius....the diameter is:

d^2=(6-2)^2+(3-1)^2

d^2=16+4

d^2=20  since d=2r, r=d/2, and r^2=d^2/4 so

r^2=5

The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
 
(h,k)=(4,2) from earlier so:

(x-4)^2+(y-2)^2=5
8 0
3 years ago
Help me out please no wrong awnsers (right awnsers only ) I ask for thanks:)
lyudmila [28]

Answer:

12 cards is the correct answer of this questions.

<em><u>plz</u></em><em><u> </u></em><em><u>mark</u></em><em><u> my</u></em><em><u> answer</u></em><em><u> as</u></em><em><u> brainlist</u></em><em><u> plzzzz</u></em><em><u> vote</u></em><em><u> me</u></em><em><u> also</u></em>

5 0
2 years ago
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

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2 years ago
Now It's Time to Practice on Your Own
AfilCa [17]
What in tarnation is this
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2 years ago
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