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2 years ago

If 6/10 = 21/K what is K

Mathematics

1 answer:

timama [110]2 years ago

3 0

You can cross multiply for this problem. So:

$\frac{6}{10}=\frac{21}{K}\\6K=210\\K=35$

So K=35!

Hope this helps! :)

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lana66690 [7]

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The value is 0.82

Step-by-step explanation:

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2 years ago

-5(x-3)= -25<br> find x pls :)

Free_Kalibri [48]

Answer:

x =8

Step-by-step explanation:

-5(x-3)= -25

we apply distributive property

-5*x +5*3 =-25

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3 years ago

Read 2 more answers

Help with this please elaborate if possible

svet-max [94.6K]

Answer:

8. yes

9. no

10. yes

Step-by-step explanation:

8. A horizontal line (y=3) is perpendicular to a vertical line (x=0).

9. A horizontal line (y=2) is parallel to a horizontal line (y=-1/2). The lines are not perpendicular.

10. A parallelogram is a rectangle if the sides are perpendicular. The slopes of the short sides are rise/run = -1, and the slopes of the long sides are rise/run = +1. These values have a product of -1, so the sides are perpendicular. The figure is a rectangle.

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2 years ago

The graph of y=f(x) is shown. a. estimate the turning point of the graph

NemiM [27]

Answer:

a) The location of the turning point is approximately $V(x,y) = (-0.25, -2,1)$ .

b) Roots are approximately $x_{1} \approx -1.3$ and $x_{2} \approx 0.8$ .

c) $f(1.5) \approx 4$

Step-by-step explanation:

a) The figure presents the graphic of a parabola, that is, a second order polynomial, with an absolute minimum (vertex). The turning point of the graphic, that is, the point in which behavior of the curve changes, is the vertex. Hence, the location of the turning point is approximately $V(x,y) = (-0.25, -2,1)$

b) According to the Quadratic Formula, second-order polynomials can have either two real roots or two conjugated complex roots. In this case, we have two real roots. A root corresponds with the point of the curve that passes through x-axis. In this case, roots are approximately $x_{1} \approx -1.3$ and $x_{2} \approx 0.8$ .

c) $f(1.5)$ is the function evaluated at $x = 1.5$ , that is, the value on y-axis associated with $x = 1.5$ . Lastly, we conclude that $f(1.5) \approx 4$ .