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AleksandrR [38]
3 years ago
11

What is the effect on the graph of the function f(x) = sqrt 10x when f(x) is replaced with f(x − 5)?

Mathematics
1 answer:
Olin [163]3 years ago
3 0

Answer:

The graph experiences a translation of 5 units to the right.



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How do you work this problem? 5 - 2x = 0
ss7ja [257]

Answer:

x = 5/2

Step-by-step explanation:

Isolate x by adding 2x to both sides, obtaining:  5 - 2x + 2x = 2x.  Then 5 = 2x, and dividing both sides by 2 results in x = 5/2.


6 0
3 years ago
What is m Any answers?
Likurg_2 [28]

Answer:

B. 68°

Step-by-step explanation:

Since, opposite sides of the quadrilateral MNPQ are parallel.

Therefore, it is a parallelogram.

Measures of the opposite angles of a parallelogram are equal.

So,

(6x - 2)° = (4x + 36)°

6x - 2 = 4x + 36

6x - 4x = 36 + 2

2x = 38

x = 38/2

x = 19

m\angle M = (6x - 2)\degree  \\  \\ m\angle M = (6 \times 19- 2)\degree  \\  \\ m\angle M = (114- 2)\degree  \\  \\  m\angle M =112\degree  \\  \\ \because m\angle M + m\angle N = 180\degree  \\ (adjacent \: angles) \\  \\ \therefore m\angle N = 180\degree   - m\angle M \\  \\ \therefore m\angle N = 180\degree   - 112 \degree \\  \\ \therefore m \angle N = 68\degree

8 0
3 years ago
Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90
s344n2d4d5 [400]

Answer:

Profit function: P(x) = -0.5x^2 + 40x - 300

profit of $50: x = 10 and x = 70

NOT possible to make a profit of $2,500, because maximum profit is $500

Step-by-step explanation:

(Assuming the correct revenue function is 90x−0.5x^2)

The cost function is given by:

C(x) = 50x + 300

And the revenue function is given by:

R(x) = 90x - 0.5x^2

The profit function is given by the revenue minus the cost, so we have:

P(x) = R(x) - C(x)

P(x) = 90x - 0.5x^2 - 50x - 300

P(x) = -0.5x^2 + 40x - 300

To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:

50 = -0.5x^2 + 40x - 300

-0.5x^2 + 40x - 350 = 0

x^2 - 80x + 700 = 0

Using Bhaskara's formula, we have:

\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600

x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70

x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10

So the values of x that give a profit of $50 are x = 10 and x = 70

To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).

The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:

x_v = -b/2a = 80/2 = 40

Using this value of x, we can find the maximum profit:

P(40) = -0.5(40)^2 + 40*40 - 300 = $500

The maximum profit is $500, so it is NOT possible to make a profit of $2,500.

3 0
3 years ago
Help asap !! will get branliest.​
kompoz [17]

Answer:

0.8

Step-by-step explanation:

(2 x 10^-4)

= 0.0002

(4x10^3)

= 4000

0.0002 x 4000 = 0.8

7 0
3 years ago
Please... I need help! ​<br>Some one to explain me plz
SVETLANKA909090 [29]
What am I supposed to be helping with the picture you took is only showing examples
7 0
3 years ago
Read 2 more answers
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