Question

Drag the numbers to order them from greatest to least, with the greatest at the top.

Answer 1

Answer: Our numbers are: $\sqrt{8/3}$,  π, 3.01245 and $\sqrt{17}$. Let's analyze them:

1) $\sqrt{8/3}= \sqrt{16/6} =4/\sqrt{6}$ and $\sqrt{6} \geq\sqrt{4}= 2$, so $4/\sqrt{6} \leq4/2 = 2$

So $\sqrt{8/3}\leq2$

2) the number pi is 3.14159265

3) this number is 3.01245, doesn't require more analyzing-

4) $\sqrt{17}$, we know that $\sqrt{16} = 4$, then $\sqrt{17} \geq 4$

So the correct order from greatest to lowest is:

$\sqrt{17}$, π , 3.01245, $\sqrt{8/3}$

You also can check it with a calculator, but it isn't the idea of the problem.

Answer 2

(√ ​17 = 4.12..., √ ​ 8/3 = 1.63..., π = 3.14...)

Greatest to least would be:
√ ​17
π
3.01245...​
√ ​ 8/3