Let A be an nxn matrix. Show that if A^(2) = 0, then I-A is nonsingular and (I-A)^(-1) = I+A
<span>Note that (I - A)(I + A) </span>
<span>= I(I + A) - A(I + A) </span>
<span>= (I - A) - (A + A^2) </span>
<span>= I - A^2 </span>
<span>= I - 0, since A^2 = 0 </span>
<span>= I. </span>
<span>Hence, I - A is non singular with inverse I + A (since the inverse is unique when it does exist)</span>
solving a triangle MNL
M=36°
N=?
L=83°
m=?
n=?
l=29
for angle N,
M + N + L=180°
or,36°+N+83°=180°
or, N=180°-36°-83°
or,N=61°
for side m, we have,
(m/sinM) = (l/ sinL)
or, m/sin36°=29/sin83°
or, m=( 29×sin36°)/sin83°
or, m= 17.17
similary, you can find out the value of n by using relation (mnn/sinN) = (l/ sinL) and solve triangle PQR
finding the area
we have,
area of triangle(A)=1/2×ab×sin C
where C is angle and a, b are sides
so area of first triangle is,
A=0.5×21×16×sin30=84 square feet
a
Area of another triangle can be findout in the same way
Answer:
C is Figure 1 and 4 and D is 1 and 2
Step-by-step explanation:
The answer is B (pictures below)