All categories

3 years ago

Jill and Erika made 4 gallons of lemonade for their lemonade stand. How many quarts did they make?

Mathematics

2 answers:

NeX [460]3 years ago

4 0

<h3>Answer: B. 16 quarts</h3>

Work Shown:

1 gallon = 4 quarts .... think 4 quarters in a dollar

4*(1 gallon) = 4*(4 quarts) ... multiply both sides by 4

4 gallons = 16 quarts

lukranit [14]3 years ago

3 0

The answer is B. 16 quarts because 4 quarts= 1 gallon

You might be interested in

(2x - 3) (4x + 1)<br><br>helping hand?

Leto [7]

(2x-3)(4x+1)=
8x^2-10x-3

4 0

3 years ago

Read 2 more answers

An artist wants to make alabaster pyramids using a block of alabaster with a volume of 576 cubic inches. She plans to make each

Musya8 [376]

<span>Volume of Pyramid = area of base * height * 1/3
Volume of Pyramid = 3 * 4 * 1/3 = 4 ins^3 </span>Theoretically the artist can make 576/4<span>= 144 pyramids out of the block of alabaster.
Hope this helps.
:-)

So ur answer is B hope this helps and branliest </span>

5 0

3 years ago

Read 2 more answers

What is the simplified form of the rational expression below? 5x^2-5/3x^2+3x

Rama09 [41]

Hi
i have just tried this equation just now.
tell me if i made some mistakes please
S=1.68-0-0+2x
A=1.68+2x

8 0

3 years ago

Someone please help and please make sure the answer is right :(

cluponka [151]

Answer:

it's 11

Have a good day!!

8 0

3 years ago

Find the midpoint of the line segment joining the points (10,7) and (negative 2,negative 7).

Basile [38]

The midpoint of the line segment joining the points (10,7) and (negative 2,negative 7) is (4, 0)

<h3><u>Solution:</u></h3>

Given that line segment joining the points (10,7) and (negative 2, negative 7)

Thus the two points are (10, 7) and (-2, -7)

The midpoint of two points $(x_1, y_1)$ and $(x_2, y_2)$ is given as:

$M(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text {Here } x_{1}=10 \text { and } y_{1}=7 \text { and } x_{2}=-2 \text { and } y_{2}=-7$

Substituting the values in formula, we get

$\begin{array}{l}{M(x, y)=\left(\frac{10+(-2)}{2}, \frac{7+(-7)}{2}\right)} \\\\ {M(x, y)=\left(\frac{10-2}{2}, \frac{7-7}{2}\right)} \\\\ {M(x, y)=(4,0)}\end{array}$

Thus the midpoint of line segment is (4, 0)

8 0

4 years ago