Answer:
First solution = 12 Liters
Second solution = 12 Liters
Third solution = 24 Liters
Step-by-step explanation:
Let the number of liters of 25% acid = y
The number of liters of 70 % acid = 2y
The number of liters of 15 % acid = 48-3y
Volume of acid in first solution= 0.15 (48-3y)
Volume of acid in second solution= 0.25y
Volume of acid in third solution= 0.7 (2y)
Volume of acid in mixture = 0.45 x48
= 21.6 liters
Assuming no loss of volume,
0.15 (48-3y) + 0.25y + 0.7 (2y) = 21.6
7.2 -0.45y + 0.25y +1.4y = 21.6
7.2+ 1.2y = 21.6
1.2y = 21.6 - 7.2
1.2 y = 14.4
y = 14.4/1.2
y = 12 liters
Substituting the value of y above:
Volume of first solution = 48-3y
= 48- 3(12)
= 48-36
= 12 liters
Volume of second solution = y
= 12 liters
Volume of third solution = 2y
= 2 (12)
= 24 liters
