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butalik [34]
3 years ago
8

Work out the area of a rectangle with base, b = 14mm and perimeter, P = 30mm

Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0

Answer:

14 mm squared is the area

Step-by-step explanation:

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Which side of the dilation corresponds to side AC of the original figure?
Sav [38]
It is A'C' because when the figure is dilatted the corresponding figure has " by it.

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Please Help ! Will Reward Brainliest
pychu [463]

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7 0
4 years ago
PLEASE HELP 25 POINTS!!
iris [78.8K]

Answer:

m= masters degree salary and b=bachelors degree salary.

m = 2b - 45000

m + b = 112000

Substitute to get

2b - 45000 + b = 112000

3b = 156000

b = 52000

So m = 59000

Check to see if these numbers work

59000 = 2*52000 - 45000 true

59000 + 52000 = 112000 true

Step-by-step explanation:

7 0
3 years ago
Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
Use the euclidean algorithm to find
kvasek [131]
A)
18=1\cdot12+6
12=2\cdot6+0
\implies\mathrm{gcd}(12,18)=6

b)
201=1\cdot111+90
111=1\cdot90+21
90=4\cdot21+6
21=3\cdot6+3
6=2\cdot3+0
\implies\mathrm{gcd}(111,201)=3

c)
1331=1\cdot1001+330
1001=3\cdot330+11
330=30\cdot11+0
\implies\mathrm{gcd}(1001,1331)=11

d)
54321=4\cdot12345+4941
12345=2\cdot4941+2463
4941=2\cdot2463+15
2463=164\cdot15+3
15=5\cdot3+0
\implies\mathrm{gcd}(12345,54321)=3

e)
5040=5\cdot1000+40
1000=25\cdot40+0
\implies\mathrm{gcd}(1000,5040)=40

f)
9888=1\cdot6060+3828
6060=1\cdot3828+2232
3828=1\cdot2232+1596
2232=1\cdot1596+636
1596=2\cdot636+324
636=1\cdot324+312
324=1\cdot312+12
312=26\cdot12+0
\implies\mathrm{gcd}(9888,6060)=12
8 0
3 years ago
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