Help me this please thank you

Mathematics

1 answer:

lidiya [134]3 years ago

6 0

M(x, y) = ((x1 + x2)/2, (y1 + y1)/2); where (x1, y1) and (x2, y2) are the coordinates of G and H respectively.

M(4, 3) = ((5 + x2)/2, (-6 + y2)/2)
(5 + x2)/2 = 4 and (-6 + y2)/2 = 3
5 + x2 = 4 * 2 = 8 and -6 + y2 = 3 * 2 = 6
x2 = 8 - 5 = 3 and y2 = 6 + 6 = 12
x2 = 3 and y2 = 12

Therefore, the coordinates of H is (3, 12)

You might be interested in

Use CALCULUS to find coordinates of the turning point on C.

antiseptic1488 [7]

Oi

Just calculating the differential. Step by step:

$y=12 \sqrt{x} -x \frac{3}{2}-10 \\ \\ y=12x^{ \frac{1}{2} } -x \frac{3}{2}-10 \ \ \ \boxed{transform \ \sqrt{x} =x^{ \frac{1}{2} }} \\ \\ Differentiating \\ \\ y'=12. \frac{1}{2}.x^{ \frac{1}{2}-1 } -1.x^{1-1}. \frac{3}{2}-0 \\ \\ y'=6.x^{ -\frac{1}{2} } -x^{0}. \frac{3}{2} \\ \\ y'=6. \frac{1}{x^{ \frac{1}{2} }} -1. \frac{3}{2} \\ \\ \boxed{y'=\frac{6}{ \sqrt{x} } -\frac{3}{2}}$

If you want to know where the tangent has no slope:

$\frac{6}{ \sqrt{x} } - \frac{3}{2} =0 \\ \\ \frac{6}{ \sqrt{x} } = \frac{3}{2} \\ \\ 3 \sqrt{x} =12 \\ \\ \sqrt{x} = \frac{12}{3} \\ \\ \sqrt{x} =4 \\ \\ (\sqrt{x})^2 =4^2 \\ \\ x=16$

3 0

3 years ago

Which shows one way to determine the factors of x^3 - 9x^2 + 5x - 45 by grouping ?

adoni [48]

You can group first two conjunctions and second two:
$x^3 - 9x^2 + 5x - 45=(x^3-9x^2)+(5x-45)$ .
In first brackets you have common $x^2$ and in second brackets common is 5:
$(x^3-9x^2)+(5x-45)=x^2(x-9)+5(x-9)=(x-9)(x^2+5)$ .

7 0

3 years ago

Thanks for the help ;)

Pani-rosa [81]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Choose the correct inequality based on the number line below

Kryger [21]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the domain and range <br> f(x)=x^3

Wittaler [7]

Answer:

Step-by-step explanation:

The domain is X value and range is Y so just put y=x^3 in desmos and the graph appears then check its range and domain from it. the range is positive and nevative infinity

6 0

3 years ago