Answer:
B
Step-by-step explanation:
dont need to know why
OOF no one answered in 4 days?! wow
Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:
P = -12xy - 56y - 42x + 8
Step-by-step explanation:
P = 2L + 2W
P = 2(4 - 7(3x + 4y)) + 2(3x(-2y))
P = 8 - 14(3x + 4y) + 6x(-2y)
P = 8 - 42x - 56y - 12xy
P = -12xy - 56y - 42x + 8
Answer:
-2
Step-by-step explanation:
Answer:
What does it even say? Plus i'm 5th grade sooo, me OUT!
Step-by-step explanation:
