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ser-zykov [4K]
3 years ago
10

Show me subtraction fractions with unlike denominator 5 grad super teacher work sheets

Mathematics
1 answer:
lawyer [7]3 years ago
5 0
1/3-1/5     

5/3-3/2    

I hoped this helped
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For a Standard Normal Distribution
Serggg [28]
In your question where ask to find the Standard Normal Distribution of the following:

give probabilities for 0<Z<infinity. For these ranges, you can read directly, for example, P(Z<1.96)=0.975. So for #1, you read directly on the line 1.3 and column 0.03. For #2, we note that the distribution is symmetrical about Z=0, so P(Z<-2.33) is the same as P(Z>2.33) which again is the same as 1-P(Z<2.33) because we know that the area under a probability distribution function adds up to 1. For the remaining questions, work is similar to #2.

8 0
3 years ago
Help please asap asap asap
EastWind [94]

Answer:1.5

Step-by-step explanation:

8 0
2 years ago
Carmen drew line A and line B in the two scatter plots shown. one scatter plot contains 12 points indicating a negative correlat
blondinia [14]

The true statement is that only line A is a well-placed line of best fit

<h3>How to determine the true statement?</h3>

The scatter plots are not given. However, the question can still be answered

The features of the given lines of best fits are:

<u>Line A</u>

  • 12 points in total
  • Negative correlation
  • Passes through the 12 points with 6 on either sides

<u>Line B</u>

  • 12 points in total
  • Positive correlation
  • Passes through the 12 points with 8 and 4 in either sides

For a line of best fit to be well-placed, the line must divide the points on the scatter plot equally.

From the given features, we can see that line A can be considered as a good line of best fit, because it divides the points on the scatter plot equally.

Read more about line of best fit at:

brainly.com/question/14279419

#SPJ1

4 0
1 year ago
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
Slav-nsk [51]

Answer:

Systolic on right

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

CV= \frac{\sigma}{\mu}

And the best estimator is \hat {CV} =\frac{s}{\bar x}

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

\bar x = 127.5, s= 18.68

So then the coeffcient of variation is given by:

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

For this case we have the following values:

\bar x = 74.2 s= 12.65

So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0
2 years ago
Match each quadratic equation with the best way to solve it. 1. 5x2 + 12x - 3 = 0 solve by square root method 2. x2 - 4x = 8 sol
Ksivusya [100]
<span>The best way to solve each equation is:
 
</span> 1) 5x2 + 12x - 3 = 0 -----> solve by quadratic formula 
 2) 4x2 - 25 = 0 -----------> solve by square root method 
 3) x2 - 5x + 6 = 0 --------> solve by factoring
 4) x2 - 4x = 8 -------------> solve by completing the square 

8 0
3 years ago
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