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Feliz [49]
2 years ago
7

Please help it’s for a grade I’ll give you Brinley if right

Mathematics
1 answer:
Vikki [24]2 years ago
8 0

Answer: D

Step-by-step explanation:

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In a unit circle, ø = 270º. Identify the terminal point and sin ø.
larisa [96]

Answer:

Terminal point (0, -1); sin Ø = -1 ⇒ A

Step-by-step explanation:

In the unit circle, Ф is the angle between the terminal side and the positive part of the x-xis

  • The terminal point on the positive part of the x-axis is (1, 0),which means Ф = 0° or 360° and cosФ = 1, sinФ = 0
  • The terminal point on the positive part of the y-axis is (0, 1),which means Ф = 90° and cosФ = 0, sinФ = 1
  • The terminal point on the negative part of the x-axis is (-1, 0),which means Ф = 180° and cosФ = -1, sinФ = 0
  • The terminal point on the negative part of the y-axis is (0, -1),which means Ф = 270° and cosФ = 0, sinФ = -1

In a unit circle

∵ Ф = 270°

→ By using the 4th rule above

∴ The terminal point is (0, -1)

∴ sinФ = -1

∴ Terminal point (0, -1); sin Ø = -1

4 0
2 years ago
Read 2 more answers
The table below represents a proportional relationship. The unit rate of the relationship is
jek_recluse [69]

Answer:

the unit rate is 3

7 0
3 years ago
Find the oth term of the geometric sequence 7, 14, 28, ...
yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

The ratio of all the adjacent terms is the same and equal to

r=2

now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

6 0
2 years ago
Scott’s piggy bank contains $5.87 worth of pennies and quarters. If the number of pennies is fifteen more than the number of qua
Elenna [48]

Answer:

23 quarters and 12 pennies

6 0
3 years ago
Simplify the scalar multiplication on the matrix.
Romashka-Z-Leto [24]

Answer:

third option

Step-by-step explanation:

Given

3 \left[\begin{array}{ccc}-2&5\\1&0\\\end{array}\right]

Multiply each element in the matrix by 3

= \left[\begin{array}{ccc}3(-2)&3(5)\\3(1)&3(0)\\\end{array}\right]

= \left[\begin{array}{ccc}-6&15\\3&0\\\end{array}\right]  

7 0
3 years ago
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