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faust18 [17]
3 years ago
8

Pythagorean theorem: Show work please free points!!!!

Mathematics
2 answers:
IgorC [24]3 years ago
6 0
So if you have a right triangle with legs legnth a and b and a hypotonuse legnth c, then a^2+b^2=c^2 given in the comments is that a=15 c=20 input and solve 15^2+b^2=20^2 225+b^2=400 subtract 225 from boths ides b^2=175 take square root of both sides b=5√7
tamaranim1 [39]3 years ago
5 0
The therorem is: 

a^{2} + b^{2} = c^{2}
or, solving for b:
b = \sqrt{c^{2}-a^{2}}

b = \sqrt{20^{2}-15^{2}}
b = \sqrt{400-225}
b = \sqrt{175}
b \approx 13.23
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W3=24<br> Question 4 options:<br><br> w = 8<br><br><br> w = 72<br><br><br> w = 12<br><br><br> w = 6
Umnica [9.8K]
The answer is w=8.....
5 0
2 years ago
Read 2 more answers
I like to help in this problem: in the course of Juan 2/9 of the students are children of 13 years, 1/4 have 14 years and the re
taurus [48]
Rest are 19/36

it is 1 -(1/4) - (2/9)
= 1-9/36 - 8/36
= (36-9-8)/36
= 19/36.
3 0
3 years ago
A square pyramid is shown sitting on its base.
sesenic [268]

Answer:

312

Step-by-step explanation:

First we find the measure of the basea and that is 144 becuase 12x12

To find one side we do b*h over 2 and that is 7x12/2 which is 42 then we know that there are 4 more of those sides and we get 42*4 168

When we add 144+168 we will get 312

5 0
3 years ago
A mine elevator was at a depth of -120 feet. After 15 seconds, the mine elevator was at a depth of -30 feet. What expression can
Dafna11 [192]

Answer:

The answers to the given question are:

i.  The equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

ii. The miner's elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e. speed =

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miner's elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

                                 = 44 seconds

So that, the distance of the elevator at this time is;

speed =

⇒ distance = speed x time

                  = 4 x 44

                  = 176

  distance = - 176 feet

The distance of the miner's elevator after 14 seconds is:

speed =

⇒ distance = speed x time

                 = 15 x 14

                 = 210

 distance = - 210 feet

Thus, after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miner's elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miner's elevator is deeper than that of the equipment.

Step-by-step explanation:

done

4 0
2 years ago
Ratio 400g : 1kg can be written in the form 1 : n find the value of n?
zvonat [6]
400 : 1kg
400 : 1000
1 : 2.5

n = 2.5
8 0
2 years ago
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