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faust18 [17]
3 years ago
8

Pythagorean theorem: Show work please free points!!!!

Mathematics
2 answers:
IgorC [24]3 years ago
6 0
So if you have a right triangle with legs legnth a and b and a hypotonuse legnth c, then a^2+b^2=c^2 given in the comments is that a=15 c=20 input and solve 15^2+b^2=20^2 225+b^2=400 subtract 225 from boths ides b^2=175 take square root of both sides b=5√7
tamaranim1 [39]3 years ago
5 0
The therorem is: 

a^{2} + b^{2} = c^{2}
or, solving for b:
b = \sqrt{c^{2}-a^{2}}

b = \sqrt{20^{2}-15^{2}}
b = \sqrt{400-225}
b = \sqrt{175}
b \approx 13.23
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Is triangle MNL congruent to triangle QNL? Why or why not? Yes, they are congruent by either ASA or AAS. Yes, they are both righ
sergij07 [2.7K]
See the attached figure which represent the rest of the question.
The rest of the question is the attached figure.
==============================================
As shown in the attached figure:
(1) ΔMNL is a right triangle at ∠MNL and ∠NML = 58°
∴ ∠L = 180° - (90°+58°) = 32°

(2) ΔQNL is a right triangle at ∠QNL and ∠QLN = 32°
∴ ∠Q = 180° - (90°+32°) = 58°

So, for both of ΔMNL and ΔQNL
1.  ∠NLM = ∠ NLQ = 32°
2.  ∠Q = ∠M = 58°
3.  side NL = side NL
∴ ΔMNL is congruent to ΔQNL by AAS

=======OR=======

So, for both of ΔMNL and ΔQNL
1.  ∠MNL = ∠QNL  = 90°
2.  side NL = side NL
3.  ∠NLM = ∠ NLQ = 32°
∴ ΔMNL is congruent to ΔQNL by ASA

=====================================
So, the correct answer is the first option

Yes, they are congruent by either ASA or AAS




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Will give brainliest !please help <br><br>4b+7b+5​
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Answer:

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