Answer:
(2x^2 + x-3)/(4x^2-9)
Step-by-step explanation:
The denominator looks like an expression in which we have applied the difference of two squares to
In that case, we know that;
a^2-b^2 = (a-b)(a+ b)
That means we would be have 2x + 3 as the other denominator factor and the expression at the denominator would be;
(2x + 3)(2x-3) = 4x^2 - 9
Also, we would have to cancel out 2x + 3 from the numerator too, so as to be left with only the binomial
That means;
(2x+3)(x-1) = 2x^2-2x+ 3x - 3 = 2x^2+x -3
So we have the original expression as;
(2x^2 + x-3)/(4x^2-9)
2x^2=(3root2)^2
2x^2=9(2)
x^2=9
x= 3,-3
x=3 because your side length can’t be negative.
<em>Answer:</em>
The inequality that is true is -5 - 3x > 10.
<em>Step-by-step explanation:</em>
if x = -6
we can subtitution x to every inequality, so :
-5 - 3x > 10
-5 - 3(-6) > 10
-5 - (-18) > 10
-5 + 18 > 10
13 > 10 [true]
-3 - 5x < -14
-3 - 5(-6) < -14
-3 - (-30) < -14
-3 + 30 < -14
27 < -14 [false]
2 - x < -3
2 - (-6) < -3
2 + 6 < -3
8 < -3 [false]
So if x=-6, inequality true is -5 - 3x > 10.
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Answer:
B: 
Step-by-step explanation:
1. Substitute 
for c: 
2. Solve substitution: 
3. Compare to calculated answers when 
4. when is
Apologies, but there is no map...?
