- ok so
- 16.(1+3) = 16 . 4 = 64
- so let's solve them
- A = (16 . 1) + (3 . 16) .. here it's right because we split the 6 on each number ... if you want a prove solve it (16 . 1 ) + (3 . 16 ) = 64
- B = (3+1) . 16 = 4 . 16 = 64
- C = (16 +3) . 1 = 19 . 1 = 19
- D = 161 + 163 = 324
so A & B = 64 .... so yeah right A & B are the correct answers
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Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
It simplifies to 27/70 if you use a calculator and do the math right
Divide the amount of money earned by the amount she got from every house.
780 / 5 = 156
156 out of 278 houses payed money. Subtract to see how many did not pay money
278 - 156 = 122
Hannah did not collect money from 122 of the houses in her neighborhood.
Answer:
yes
Step-by-step explanation:
-8x-2y<6
Substitute the point into the inequality and see if it is true
-8(3) -2(2) <6
-24-4<6
-28<6
This is true so it is a solution