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2 years ago

Six friends visited a museum to

Mathematics

2 answers:

Genrish500 [490]2 years ago

8 0

Answer:

x+2

Step-by-step explanation:

AleksAgata [21]2 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

NO LINKS OR FILES ONLY ANSWER IF YOU KNOW IT PLEASE

agasfer [191]

Answer:

Step-by-step explanation:

100% is the whole graph so 23% of 100 is 23

5 0

2 years ago

What is the range of the function y = x 2?

Leno4ka [110]

Answer:

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Step-by-step explanation:

Given the function

$y=x^2$

We know that the range of a function is the set of values of the dependent variable for which a function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)$

$f\left(x\right)\ge \:0$

Thus,

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

5 0

2 years ago

Explain the difference between the graphs of :

charle [14.2K]

Answer:

The only difference is that for any positive value of 'x' g(X) and h(X) will be same and for any negative value of 'x' g(x) and h(x) will be different.

Step-by-step explanation:

Given

$f(x)= |x|$

$g(x) = |x+5|\\\\h(x)= |x| +5$

|x| is modulus of x so modulus makes negative value as psoitive

for example

$|3|= 3$

$|-3|=3$

now we will solve for the above

For $x=4$

$g(4)=|4+5|\\=|9|\\=9$

and

$h(4)=|4| +5\\=4 +5\\=9$

Now for $x=-4$

$g(-4)=|-4+5|\\=|1|\\=1$

and

$h(-4)=|-4| +5\\=4 +5\\=9$

so for positive value it is same and for negative value it is different

7 0

3 years ago

Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$

horrorfan [7]

Answer:

$A +B+C+D = 3$ is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

$A+B+C+D = ?$ if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under $\sqrt$ (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

$\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \ (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}$

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, $A +B+C+D = 5+6-10+2 = \bold3$

5 0

3 years ago

Use the slope formula to find the slope of the line in the graph shown above.

Artist 52 [7]

Answer:

Step-by-step explanation:

5 0

2 years ago