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3 years ago

5x-3=3x+8 ~~~~ 2 X=? The lines a fraction

1 answer:

3 0

$\dfrac{5x-3}{2}=3x+8\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\\\5x-3=6x+16\ \ \ \ |add\ 3\ to\ both\ sides\\\\5x=6x+19\ \ \ \ |subtract\ 6x\ from\ both\ sides\\\\-x=19\ \ \ \ |change\ signs\\\\\boxed{x=-19}$

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PLEASE HELP!!

zloy xaker [14]

I think it’s SSS but I’m not 100% sure

8 0

3 years ago

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You need to mix 42 kilograms of mortar. Each kilogram of mortar mix requires 0.03 liters of water. How many liters of water do y

Yakvenalex [24]

42*.03 liters = <span>1.26 liters</span>

6 0

4 years ago

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Janet's recipe calls for 6/8 cup of milk. what is this fraction in simplest form?

insens350 [35]

You can easily simpligy this fraction by taking a 2 out of the top and bottom of it.

6/2=3
8/2=4

Your answer is 3/4

I hope this helps!

4 0

4 years ago

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In triangle PQR, the length of PQ is 5 inches and the length of PR is 9 inches. Give all the possible whole-number lengths of si

8_murik_8 [283]

Answer:

$4$

5, 6, 7, 8, 9, 10, 11, 12, and 13.

Step-by-step explanation:

We can use the triangle inequality. By the triangle inequality, the sum of any two sides of a triangle must be greater than the remaining side.

In other words, the sum of the two shorter sides must be greater than the longest side.

We know that PQ is 5 and PR is 9.

For the first case, let's say that neither PQ nor PR is the longest side. Instead, QR is the longest side. Then their sum must be greater than QR. Thus:

$5+9>QR\Rightarrow QR$

However, for the second case, let's say that QR is not the longest side. In this case, PR will be the longest side. Therefore, QR plus PQ must be greater than PR:

$QR+5>9\Rightarrow QR>4$

Thus, we have a compound inequality:

$4$

Therefore, the possible whole-number lengths of QR are:

5, 6, 7, 8, 9, 10, 11, 12, and 13.

5 0

3 years ago

Please help. Will give brainliest. And I need step by step please

Elan Coil [88]

Answer: 500cm squared

Step-by-step explanation:

To figure out the area, here are the steps

First, seperate the parallelogram into 2 triangles and a rectangle.

Secondly, we see it has figured out the area of the triangle which is 25, so we can assume that the other triangle is also 25. So the area of the two triangles are 25 + 25 = 50

Then, if we look at what it has labeled, we would know that the length of the parallelogram is 50, BUT this 50 contains ONE length of the triangle, which means to get the actual length of the rectangle, we must subtract a length of a triangle from 50.

That's 50 - 5 = 45. Therefore the area of the rectangle is (length times width) 45 ✕ width = the area of the rectangle.

Now we realize that we don't know the width of the rectangle, we can figure that out by back-tracking from the area of the triangle.

We know that area of a triangle is length times height divided by 2, so 25 ✕ 2 divided by legth would get us the height of the triangle. 25 ✕ 2 ÷ 5 = 10

Now we can figure out the area of the rectangle. 45 ✕ 10 = 450

Add the rectangle and the triangles together, you get -- 450 + 50 = 500 (cm squared）

7 0

3 years ago

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