Answer: B) Infinitely many solutions; both equations are equivalent
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Work Shown:
x+y = 4 ... start with the first equation
x + (-x+4) = 4 ... replace y with (-x+4)
x-x+4 = 4
0x+4 = 4
0+4 = 4
4 = 4 ... this is a true statement regardless of what x you pick
So there are infinitely many solutions. Each solution (x,y) is of the form (x,-x+4). All solutions fall on the line y = -x+4 which is equivalent to x+y = 4. Note how we add x to both sides.
Or you could start with x+y = 4 and subtract x from both sides to get y = -x+4. Either way, we're dealing with the same equation which is why they both graph out the same line.
Answer:
a7 = 36
Step-by-step explanation:
Here, we are to use the recursive formula to calculate the 7th term( we add the preceding term to 4 so as to get the succeeding term)
a1 = 12
using the recursive formula given in the question
a2 = 12 + 4 = 16
a3 = 16 + 4 = 20
a4 = 20 + 4 = 24
a5 = 24 + 4 = 28
a6 = 28 + 4 = 32
a7 = 32 + 4 = 36
Answer:

Step-by-step explanation:
The function that could model this periodic phenomenon will be of the form

The tide varies between 3ft and 9ft, which means its amplitude
is

and its midline
is
.
Furthermore, since at
the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is
.
The period of the full cycle is 14 hours, which means


giving us

With all of the values of the variables in place, the function modeling the situation now becomes

Answer:
A. 0.25 (rounded)
B. 0.19 (rounded)
C. 0.17 (rounded)
D. 0.17 (rounded)
Step-by-step explanation:
Hope that helped!
Area of first rectangle= 5×2=10units
Area of second rectangle= 3×2= 6 units
Area of third rectangle = 5×2= 10 units
Now,
Total area of figure = 10+6+10= <u>26units✓</u>