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andreyandreev [35.5K]

3 years ago

13

Marthy has exactly five blue pens,six black pens,and four red pens in his knapsack. if he pulls out one pen at random from his k

napsack.what is the probability that the pen is either red or black?

1 answer:

Arte-miy333 [17]3 years ago

5 0

(red pens + black pens) / total pens
(4 + 6) / 15 = 10/15 = 2/3

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NNADVOKAT [17]

Answer: $\frac{2x(5x + 1)}{4x - 1}$

<u>Step-by-step explanation:</u>

$\frac{4x^{3}-12x^{2}}{4x^{2}+7x - 2}$ ÷ $\frac{2x^{2}-6x}{5x^{2}+11x + 2}$

= $\frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)}$ ÷ $\frac{2x(x - 3)}{(5x + 1)(x + 2)}$

= $\frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)}$ x $\frac{(5x + 1)(x + 2)}{2x(x - 3)}$

= $\frac{2x(5x + 1)}{4x - 1}$

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3 years ago

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2 years ago

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goldfiish [28.3K]

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3 years ago

Given log630 ≈ 1.898 and log62 ≈ 0.387, log615 =

Tom [10]

$\log_630\approx1.898\\\\\log_62\approx0.387\\\\\log_615=\log_6\dfrac{30}{2}=\log_630-\log_62\approx1.898-0.387=1.511\\\\Used:\\\\\log_ab-\log_ac=\log_a\dfrac{b}{c}$

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2 years ago

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ILL BRAINLIEST YOU PLEASE HELP ME

Aleksandr-060686 [28]

Answer:

x = 71/5 (as an improper fraction)

x = 14 1/5 (as a proper fraction

x = 14.2 (as a decimal)

Step-by-step explanation:

It's a rectangle so the diagonals are equal

7x - 9 = 2x + 62

Subtract 2x from both sides

5x - 9 = 62

Add 9 to both sides

5x = 71

Divide both sides by 5

x = 71/5 (as an improper fraction)

x = 14 1/5 (as a proper fraction

x = 14.2 (as a decimal)

8 0

2 years ago

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